__________ is the time taken to locate the disk arm to a specified track for data read/write.
Seek time
When a computer needs to read or write data to a hard disk drive, several steps are involved. One crucial step is moving the disk arm to the correct location on the disk surface where the data is stored. This movement is what the question is asking about.
Let's break down the components of disk access time to understand which one fits the description:
Based on these definitions, the time taken specifically to move the disk arm to a specified track is the seek time.
Here's a simple comparison of the times involved in disk access:
| Component | Description |
|---|---|
| Seek Time | Time to move arm to the correct track. |
| Rotational Delay | Time to wait for the correct sector to rotate under the head. |
| Transfer Time | Time to read or write the data. |
| Disk Access Time | Total time (Seek + Rotational Delay + Transfer). |
The question specifically asks about the time to locate the disk arm to a specified track, which directly corresponds to the definition of seek time.
| Term | Meaning |
|---|---|
| Track | A concentric ring on the disk surface. |
| Sector | A segment or division of a track. |
| Cylinder | A set of tracks at the same radial position on all disk surfaces. |
| Disk Arm | Mechanical arm holding the read/write heads. |
| Read/Write Head | Component that reads data from or writes data to the disk surface. |
The total disk access time can be represented by the formula:
\( \text{Disk Access Time} = \text{Seek Time} + \text{Rotational Delay} + \text{Transfer Time} \)
Understanding these individual components is essential for evaluating the performance of a hard disk drive. Seek time is often the most significant factor contributing to the total access time, especially for random data access.
Which of the following can be said about primary storage in comparison with secondary storage?
For a magnetic disk with concentric circular tracks, the seek latency is not linearly proportional to the seek distance due to
If one track of data can be transferred per revolution, then what is the data transfer rate ?
Given below are two statements:
Statement I: The disk has a total number of 2000 cylinders.
Statement II: 51200 bytes is not a valid block size for the disk.
In the light of the above statements, choose the correct answer from the options given below:
If T is the capacity of a track in bytes, and S is the capacity of each surface in byte, then (T, S) = _____.