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Question

_________ is the maximum bending moment of a simply supported beam (length = L metre) with a point load of "W" kN at its center?

The correct answer is

W × \((\frac{L}{4})\) kNm

Maximum Bending Moment for Simply Supported Beam

Let's find the maximum bending moment for a simply supported beam carrying a point load at its center.

A simply supported beam is supported at two points and is free to rotate at the supports. A point load is a concentrated load applied at a single point on the beam.

For a simply supported beam of length \(L\) metres with a point load \(W\) kN acting exactly at the center (at a distance \(L/2\) from each support), we can determine the support reactions and the bending moment.

Calculating Support Reactions

Let the supports be at points A and B. Due to the symmetry of the beam and the central load, the reactions at both supports will be equal.

  • Total downward load = \(W\) kN
  • Total upward reaction = \(R_A + R_B\)
  • For equilibrium, \(R_A + R_B = W\)
  • Due to symmetry, \(R_A = R_B\)
  • Therefore, \(2R_A = W\), which means \(R_A = \frac{W}{2}\) kN
  • And \(R_B = \frac{W}{2}\) kN

Calculating Bending Moment

The bending moment at any section of the beam is calculated by considering the forces to one side of the section. For a simply supported beam with a central point load, the maximum bending moment occurs at the point where the shear force is zero, which is under the central point load.

Consider a section at a distance \(x\) from support A, where \(0 \le x \le \frac{L}{2}\). The bending moment \(M(x)\) at this section is due to the reaction at A:

\(M(x) = R_A \times x = \frac{W}{2} \times x\)

The bending moment increases linearly from 0 at support A to its maximum value at the center.

Finding Maximum Bending Moment

The maximum bending moment occurs at the center of the beam, where \(x = \frac{L}{2}\).

Maximum bending moment = \(M\left(\frac{L}{2}\right) = \frac{W}{2} \times \frac{L}{2}\)

Maximum bending moment = \(\frac{W \times L}{4}\)

So, the maximum bending moment is \(\frac{WL}{4}\) kNm.

Comparing this with the given options:

  • Option 1: \(W \times \left(\frac{L}{3}\right)\) kNm
  • Option 2: \(W \times L\) kNm
  • Option 3: \(W \times \left(\frac{L}{2}\right)\) kNm
  • Option 4: \(W \times \left(\frac{L}{4}\right)\) kNm

The derived formula matches Option 4.

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Important Questions from Shear Force and Bending Moment

  1. For a simply supported beam of length L with a triangular load that varies gradually (linearly) from zero at both ends to w per unit length at the centre, the maximum bending moment is

  2. For simply supported beams, the bending moment at supports (or ends) is always

  3. A cantilever of length L carries a gradually (linearly) varying load from zero at its free end to w per unit length at the fixed end. The product of deflection and flexural rigidity at the free end is

  4. If the shear force at a section of a simply supported beam is zero, the bending moment at the section is

  5. Shear force at any point of the beam is the algebraic sum of

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