In which quadrant is the point (–4, –3) located? A. I B. II C. III D. IV
C
The coordinate plane, also known as the Cartesian plane, is formed by two perpendicular number lines: the horizontal x-axis and the vertical y-axis. They intersect at a point called the origin (0, 0).
These two axes divide the plane into four regions called quadrants. The quadrants are numbered counterclockwise, starting from the upper right region.
| Quadrant | x-coordinate sign | y-coordinate sign | Point example |
|---|---|---|---|
| I | + | + | (2, 5) |
| II | – | + | (–2, 5) |
| III | – | – | (–2, –5) |
| IV | + | – | (2, –5) |
We are given the point with coordinates $\left(x, y\right) = \left(–4, –3\right)$.
Let's analyze the signs of its coordinates:
We need to find the quadrant where both the x-coordinate and the y-coordinate are negative.
Comparing the signs of the coordinates of the point (–4, –3) with the signs in each quadrant:
Since both the x-coordinate (–4) and the y-coordinate (–3) are negative, the point (–4, –3) is located in the Quadrant III.
| Concept | Description |
|---|---|
| Coordinate Plane | Formed by x and y axes intersecting at the origin. |
| Quadrants | Four regions of the coordinate plane defined by the axes. |
| Point (–4, –3) | Has a negative x-coordinate (–4) and a negative y-coordinate (–3). |
| Quadrant III | The region where both x and y coordinates are negative. |
Points that lie on the axes are not considered to be in any quadrant.
Understanding the signs of coordinates in each quadrant is fundamental for plotting points and solving geometry problems on the coordinate plane.
The area of a quadrilateral whose vertices are (3,0), (4,5), (-1,4) and (-2,-1) taken in order, is:
The coordinates of a point A, where AB is the diameter of a circle whose centre is (2, -3) and B is (1, 4) is:
The ratio between the radius of the base and the height of a cylinder is 3:4. If its volume is 38,808 cm³, then using \( \pi = \frac{22}{7} \), find the diameter of the cylinder.
The ratio between the radius of the base and the height of a cylinder is 3:4. If its volume is 38,808 cm³, then using \( \pi = \frac{22}{7} \), find the diameter of the cylinder.
In ΔABC if ∠A = 50° and ∠B = 70°, find the measure of exterior angle A.