All Exams Test series for 1 year @ тВ╣349 only
Question

In which of the following practical situations, Poisson Distribution can be used?

A. Number of customers arriving at the super markets per hour.

B. Number of typographical errors per page in a typed material.

C. Number of accidents taking place per day on a busy road.

D. Dice throwing problems.

E. Number of defective material say, blades, etc. in a packing manufactured by a good concern.

Choose the most appropriate answer from the options given below:

The correct answer is

A, B, C and E only

Understanding Poisson Distribution Applications

The Poisson Distribution is a discrete probability distribution that expresses the probability of a given number of events occurring in a fixed interval of time or space if these events occur with a known constant mean rate and independently of the time since the last event.

For a situation to be modeled by a Poisson distribution, the following conditions should generally be met:

  • Events are discrete (countable).
  • Events occur randomly in a fixed interval of time or space.
  • The occurrence of one event does not affect the probability of another event occurring (events are independent).
  • The average rate of events per interval is constant.
  • It is possible for more than one event to occur in the interval, and for the number of events to be potentially infinite (though the probability becomes very small for large numbers).

Analyzing Each Practical Situation for Poisson Distribution

Let's examine each given situation to determine if it fits the characteristics of a Poisson Distribution:

A. Number of customers arriving at the super markets per hour.

  • Events are discrete (counting individual customers).
  • Events occur randomly within a fixed time interval (per hour).
  • Customer arrivals can often be considered independent.
  • The average arrival rate per hour might be assumed constant for certain periods.
  • This situation is a classic example where Poisson distribution is often used to model the arrival rate.

This situation fits the Poisson distribution criteria.

B. Number of typographical errors per page in a typed material.

  • Events are discrete (counting individual errors).
  • Events occur randomly within a fixed space (per page).
  • Typographical errors can often be considered independent.
  • The average error rate per page might be assumed constant for a given typist and material.
  • This situation is another common example of Poisson distribution application.

This situation fits the Poisson distribution criteria.

C. Number of accidents taking place per day on a busy road.

  • Events are discrete (counting individual accidents).
  • Events occur randomly within a fixed time interval (per day).
  • While complex factors are involved, for modeling purposes, accidents in a busy system can often be treated as occurring independently.
  • The average accident rate per day might be assumed relatively constant, especially over short periods or under similar conditions.
  • This is a typical application area for Poisson distribution in traffic analysis.

This situation fits the Poisson distribution criteria.

D. Dice throwing problems.

  • Dice throwing problems typically involve a fixed number of trials (each throw) and the outcome of each trial is one of a finite set of possibilities (1 to 6).
  • If you are counting the number of times a specific outcome occurs in a fixed number of throws, this is modeled by the Binomial Distribution. The Binomial distribution applies when you have a fixed number of independent Bernoulli trials.
  • The Poisson distribution models the number of events in an interval, not the outcomes of fixed trials.

This situation does not fit the Poisson distribution criteria; it fits the Binomial distribution.

E. Number of defective material say, blades, etc. in a packing manufactured by a good concern.

  • Events are discrete (counting individual defective items).
  • Events occur within a fixed "space" or "volume" (a packing/batch of manufactured items).
  • Defects can often be considered independent from one item to the next.
  • Since it's a "good concern," the probability of any single item being defective is likely very small. The total number of items in a packing/batch is typically large.
  • This scenario describes a situation where the Binomial Distribution (fixed number of items, small probability of defect) can be accurately approximated by the Poisson Distribution when the number of trials (items) is large and the probability of success (defect) is small. It is a common application of Poisson approximation to Binomial, or sometimes considered a direct Poisson process if viewed as defects occurring randomly in a large production volume.

This situation fits the Poisson distribution criteria (often as an approximation of Binomial distribution). It's a classic example where Poisson is used.

Summary of Analysis

Based on the analysis:

  • A, B, C, and E are practical situations where the Poisson Distribution (or its approximation) can be used.
  • D is a situation typically modeled by the Binomial Distribution.

Therefore, the situations where Poisson Distribution can be used are A, B, C, and E.

Revision Table: Situations and Appropriate Distributions

Situation Applicable Distribution Reasoning
A. Customer arrivals per hour Poisson Number of random events in a fixed time interval.
B. Typographical errors per page Poisson Number of random events in a fixed space.
C. Accidents per day Poisson Number of random events in a fixed time interval.
D. Dice throwing problems Binomial Fixed number of trials, probability of specific outcome.
E. Defective items in a batch Poisson (approximation of Binomial) Number of rare events in a large sample/volume.

Additional Information on Probability Distributions

Understanding different probability distributions is crucial in statistics. Here are a few points related to the distributions discussed:

  • Poisson Distribution: Used for modeling the number of events occurring in a fixed interval when events are rare, independent, and occur at a constant average rate ($\lambda$). The probability mass function is $P(X=k) = \frac{e^{-\lambda}\lambda^k}{k!}$. The mean and variance are both equal to $\lambda$.
  • Binomial Distribution: Used for modeling the number of successes in a fixed number of independent Bernoulli trials, where each trial has only two possible outcomes (success/failure) and a constant probability of success ($p$). The probability mass function is $P(X=k) = \binom{n}{k}p^k(1-p)^{n-k}$, where $n$ is the number of trials and $k$ is the number of successes. The mean is $np$ and the variance is $np(1-p)$.
  • Poisson Approximation to Binomial: When the number of trials ($n$) in a Binomial distribution is large and the probability of success ($p$) is small, the Binomial distribution can be approximated by the Poisson distribution with parameter $\lambda = np$. This approximation is often used in situations like counting defects in large batches (as in situation E) or rare events.
  • Discrete vs. Continuous Distributions: Poisson and Binomial distributions are discrete, meaning they model countable outcomes. Continuous distributions (like the Normal or Exponential distribution) model outcomes that can take any value within a range.
Was this answer helpful?

Important Questions from Binomial Distribution

  1. Indicate the correct answer for the combination from the following regarding the conditions for the applicability of a binominal distribution:

    (a) There are n independent trials

    (b) Each trial has only two possible outcomes

    (c) The probabilities of two outcomes do not remain constant

    (d) The trials are independent

    Which of the following options is correct?

  2. For Binomial distribution, n = 10 and p = 0.6, E(X 2) (second moment about origin) is:

  3. The mean and variance of binomial distribution B (x, n, p) are 4 and \(\dfrac{4}{3}\) respectively. What is the probability of getting 2 successes?

  4. Find out the fallacy if any in the statement:

    “The mean and the variance of a binomial distribution is 16.2 and 29.4 respectively.”

  5. If log e(x) is normally distributed with mean 1 and variance 4, then P(0.5 < x < 2) is:

    (where the area between z = 0 and z = 0.25 is 0.0987 and the area between z = 0 and z = 0.5 is 0.1915)

Need Expert Advice?

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App