In the Rutherford's scattering experiment, deflection of alpha (α) particles is due to
Force of repulsion
Rutherford's alpha ($\alpha$) particle scattering experiment was a landmark study that led to the discovery of the atomic nucleus. In this experiment, a beam of positively charged alpha particles was directed at a thin gold foil. The observation of how these alpha particles behaved after interacting with the gold atoms provided crucial insights into the structure of the atom.
Alpha particles are composed of two protons and two neutrons, giving them a net positive charge ($+2e$). According to Rutherford's model, an atom consists of a tiny, dense, positively charged nucleus at its center, with electrons orbiting around it. When an alpha particle approaches an atom in the gold foil, its interaction with the atom's components determines its path.
The deflection or scattering of the alpha particles in Rutherford's experiment is primarily due to the electrostatic force of repulsion between the positively charged alpha particle and the positively charged atomic nucleus. As an alpha particle approaches the nucleus, this repulsive force causes its trajectory to bend, leading to deflection. The closer the alpha particle gets to the nucleus, the stronger the repulsive force, and thus, the greater the angle of deflection. Some alpha particles even experienced large deflections, some almost 180 degrees, indicating a direct collision with the highly dense, positively charged nucleus.
Therefore, the fundamental reason for the observed deflection of alpha particles in Rutherford's scattering experiment is the strong electrostatic force of repulsion between the positively charged alpha particles and the positively charged atomic nuclei.
If $M$ is the mass of water that rises in a capillary tube of radius $r$, then what would be the total mass of water that rises if a capillary tube of radius $r$ and another capillary tube of radius $2r$ are simultaneously placed in water, assuming identical liquid and material properties?
The diameter of an atom is
The ratio of specific charge of a proton and a α-particle is
The ratio of radii of two nuclei having atomic mass numbers 27 and 8 respectively, will be:
A $Be^{3+}$ ion, initially in its second excited state, absorbs a photon of wavelength $601.6\text{ A}$. The radius of the ion in the resulting excited state in terms of Bohr radius $a_0$ will be (Take $hc = 12500\text{ eV-A}$)