Logic of Letter Triad Transformation
The question asks us to identify a specific logic or pattern governing the transformation of letter groups within a triad. We are given two examples (BLOW - WLBO - LOBW and LEAF - FELA - EALF) and need to find which of the provided options follows the same transformation rules.
Analyzing the Pattern in Given Examples
Let's break down the first example: BLOW to WLBO to LOBW.
Consider the positions of the letters in the first word: B is 1st, L is 2nd, O is 3rd, W is 4th. We can write this as (1 2 3 4).
- BLOW (Positions: 1 2 3 4)
- The second word is WLBO. Let's see how the letters from BLOW map to WLBO. W is the 4th letter, L is the 2nd, B is the 1st, and O is the 3rd. So, the transformation rule from the first word to the second word is taking the letters in the order: 4th, 2nd, 1st, 3rd. Let's represent this permutation as (4 2 1 3).
- Applying (4 2 1 3) to BLOW: B(1) L(2) O(3) W(4) → W(4) L(2) B(1) O(3) = WLBO. This matches.
- Now let's analyze the transformation from the second word (WLBO) to the third word (LOBW). Let's consider the positions in WLBO as 1' 2' 3' 4'.
- The third word is LOBW. L is the 2nd letter (of WLBO), O is the 4th, B is the 3rd, and W is the 1st. So, the transformation rule from the second word to the third word is taking the letters in the order: 2nd, 4th, 3rd, 1st. Let's represent this permutation as (2' 4' 3' 1').
- Applying (2' 4' 3' 1') to WLBO: W(1') L(2') B(3') O(4') → L(2') O(4') B(3') W(1') = LOBW. This also matches.
Let's confirm this logic using the second example: LEAF - FELA - EALF.
- LEAF (1 2 3 4)
- Applying the first rule (4 2 1 3): L(1) E(2) A(3) F(4) → F(4) E(2) L(1) A(3) = FELA. Correct.
- FELA (1' 2' 3' 4')
- Applying the second rule (2' 4' 3' 1'): F(1') E(2') L(3') A(4') → E(2') A(4') L(3') F(1') = EALF. Correct.
The logic is consistent across both examples:
- Rule 1: Word 1 (positions 1 2 3 4) → Word 2 uses permutation (4 2 1 3).
- Rule 2: Word 2 (positions 1' 2' 3' 4') → Word 3 uses permutation (2' 4' 3' 1').
Evaluating the Options Based on the Logic
Now, we will apply these two rules to each option to see which one fits.
Option 1: MOVE - EOMV - VOME
- First word: MOVE (1 2 3 4)
- Apply Rule 1 (4 2 1 3): M(1) O(2) V(3) E(4) → E(4) O(2) M(1) V(3) = EOMV. (This part matches)
- Second word: EOMV (1' 2' 3' 4')
- Apply Rule 2 (2' 4' 3' 1'): E(1') O(2') M(3') V(4') → O(2') V(4') M(3') E(1') = OVME.
- The expected third word is OVME, but the option provides VOME. Therefore, Option 1 is incorrect.
Option 2: TOUR - OTUR - ROUT
- First word: TOUR (1 2 3 4)
- Apply Rule 1 (4 2 1 3): T(1) O(2) U(3) R(4) → R(4) O(2) T(1) U(3) = ROTU.
- The expected second word is ROTU, but the option provides OTUR. Therefore, Option 2 is incorrect.
Option 3: CLAW - CALW - WALC
- First word: CLAW (1 2 3 4)
- Apply Rule 1 (4 2 1 3): C(1) L(2) A(3) W(4) → W(4) L(2) C(1) A(3) = WLCA.
- The expected second word is WLCA, but the option provides CALW. Therefore, Option 3 is incorrect.
Option 4: FANG - GAFN - ANFG
- First word: FANG (1 2 3 4)
- Apply Rule 1 (4 2 1 3): F(1) A(2) N(3) G(4) → G(4) A(2) F(1) N(3) = GAFN. (This part matches)
- Second word: GAFN (1' 2' 3' 4')
- Apply Rule 2 (2' 4' 3' 1'): G(1') A(2') F(3') N(4') → A(2') N(4') F(3') G(1') = ANFG. (This part matches)
- Both transformations match the expected logic. Therefore, Option 4 is correct.
Final Answer Confirmation
The sequence FANG - GAFN - ANFG correctly follows the established pattern:
- From FANG to GAFN: The letters are rearranged according to the (4 2 1 3) pattern.
- From GAFN to ANFG: The letters are rearranged according to the (2' 4' 3' 1') pattern.