In supersonic section of nozzle of accelerating flow the area along flow direction
increases
Nozzles are devices designed to increase the velocity of a fluid. The way the area of a nozzle changes along the direction of flow depends on whether the flow is subsonic (velocity less than the speed of sound) or supersonic (velocity greater than the speed of sound), and whether the flow is accelerating or decelerating.
For compressible flow, the relationship between the change in area ($\frac{dA}{A}$) and the change in velocity ($\frac{dV}{V}$) is given by the area-velocity relation:
\begin{equation} \frac{dA}{A} = \frac{dV}{V}(M^2 - 1) \end{equation}
Where:
We are interested in accelerating flow, which means the velocity is increasing along the flow direction. Therefore, $dV$ must be positive ($dV > 0$). Now let's consider the effect of the Mach number ($M$):
A nozzle designed to accelerate flow from subsonic to supersonic speeds is called a convergent-divergent nozzle. The flow converges to accelerate up to Mach 1 at the throat (minimum area) and then diverges to accelerate into the supersonic regime.
The question specifically asks about the supersonic section of a nozzle that has accelerating flow. In the supersonic section, the Mach number is greater than 1 ($M > 1$). As explained by the area-velocity relation, to achieve acceleration ($dV > 0$) in the supersonic regime, the area must increase ($dA > 0$) along the flow direction.
Therefore, in the supersonic section of a nozzle with accelerating flow, the area along the flow direction increases.
The smallest section of a nozzle is known as the:
In a nozzle, steam is flowing. If the back pressure is equal to the critical pressure, the mass flow rate of steam is :
Supersaturated expansion of steam through the nozzle results in:
Mach number greater than unity implies that the flow is
Which of the following will be the result after the application of nozzle?