In pure inductive circuit, the power is
zero
Let's analyze the power consumption in a circuit containing only an inductor (a pure inductive circuit) when connected to an AC voltage source.
A pure inductive circuit is an electrical circuit that contains only inductance and no resistance or capacitance. In such a circuit, the inductor resists changes in electric current.
In AC circuits, power can be categorized into:
The question asks about "the power," which typically refers to the real power (average power consumed).
In a pure inductive circuit, the current lags behind the voltage by a phase angle of 90 degrees (or $\frac{\pi}{2}$ radians). This phase difference is crucial for determining power consumption.
The formula for real power (P) in an AC circuit is given by:
$$ P = V_{rms} \times I_{rms} \times \cos(\phi) $$
Where:
For a pure inductive circuit, the phase angle $\phi$ is $90^\circ$. The cosine of this angle is:
$$ \cos(90^\circ) = 0 $$
Substituting this value into the power formula:
$$ P = V_{rms} \times I_{rms} \times 0 $$
$$ P = 0 $$
The inductor stores energy from the source during one half of the AC cycle (building up its magnetic field) and returns this stored energy back to the source during the other half of the cycle (as the magnetic field collapses). Because energy is only stored and returned, and not dissipated as heat (like in a resistor), the net energy consumed by the inductor over a full cycle is zero. Therefore, the average power, or real power, in a pure inductive circuit is zero.
Based on the phase relationship between voltage and current and the power formula, the power consumed in a pure inductive circuit is consistently zero.
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