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Question

In phase modulation, frequency deviation is-

The correct answer is

Directly proportional to the amplitude of the modulating signal

Understanding Phase Modulation (PM)

Phase modulation (PM) is a type of angle modulation where the phase of a carrier signal is varied in proportion to the instantaneous amplitude of the modulating signal. Unlike frequency modulation (FM), where the instantaneous frequency is directly proportional to the modulating signal's amplitude, in PM, it's the phase that is directly modulated.

Mathematical Representation of Phase Modulation

Let the unmodulated carrier signal be represented as:

\(c(t) = A_c \cos(\omega_c t + \phi_c)\)

Where:

  • \(A_c\) is the carrier amplitude
  • \(\omega_c = 2\pi f_c\) is the carrier angular frequency
  • \(\phi_c\) is the initial phase

Let the modulating signal be \(m(t)\). In phase modulation, the instantaneous phase \(\theta_i(t)\) of the modulated signal is given by:

\(\theta_i(t) = \omega_c t + \phi_c + k_p m(t)\)

Where \(k_p\) is the phase sensitivity of the modulator (in radians/Volt or radians/Unit of \(m(t)\)). The PM signal is then:

\(s_{PM}(t) = A_c \cos(\theta_i(t)) = A_c \cos(\omega_c t + \phi_c + k_p m(t))\)

Frequency Deviation in Phase Modulation Explained

The instantaneous angular frequency \(\omega_i(t)\) of any angle-modulated signal is the time derivative of its instantaneous phase \(\theta_i(t)\). For PM, we have:

\(\omega_i(t) = \frac{d\theta_i(t)}{dt} = \frac{d}{dt}(\omega_c t + \phi_c + k_p m(t))\)

\(\omega_i(t) = \omega_c + k_p \frac{dm(t)}{dt}\)

The instantaneous frequency \(f_i(t) = \frac{\omega_i(t)}{2\pi}\) is:

\(f_i(t) = \frac{\omega_c}{2\pi} + \frac{k_p}{2\pi} \frac{dm(t)}{dt} = f_c + \frac{k_p}{2\pi} \frac{dm(t)}{dt}\)

The instantaneous frequency deviation \(\Delta f(t)\) from the carrier frequency \(f_c\) is the difference between the instantaneous frequency and the carrier frequency:

\(\Delta f(t) = f_i(t) - f_c = \frac{k_p}{2\pi} \frac{dm(t)}{dt}\)

This formula shows that the frequency deviation in phase modulation is proportional to the derivative of the modulating signal, not the signal itself.

Let's consider a single-tone modulating signal \(m(t) = A_m \cos(\omega_m t)\), where \(A_m\) is the amplitude and \(\omega_m = 2\pi f_m\) is the angular frequency of the modulating signal. The derivative of the modulating signal is:

\(\frac{dm(t)}{dt} = \frac{d}{dt}(A_m \cos(\omega_m t)) = -A_m \omega_m \sin(\omega_m t)\)

Substituting this into the frequency deviation formula:

\(\Delta f(t) = \frac{k_p}{2\pi} (-A_m \omega_m \sin(\omega_m t))\)

The maximum frequency deviation, often simply referred to as the frequency deviation (\(\Delta f_{max}\)), is the peak value of \(|\Delta f(t)|\). This occurs when \(|\sin(\omega_m t)| = 1\):

\(\Delta f_{max} = \frac{k_p}{2\pi} A_m \omega_m = \frac{k_p}{2\pi} A_m (2\pi f_m) = k_p A_m f_m\)

From this formula, we can clearly see the dependencies of the maximum frequency deviation in phase modulation:

  • It is directly proportional to the phase sensitivity \(k_p\).
  • It is directly proportional to the amplitude of the modulating signal \(A_m\).
  • It is directly proportional to the frequency of the modulating signal \(f_m\).

Analyzing the Options

Let's evaluate each provided option based on our derivation of the frequency deviation (\(\Delta f_{max} = k_p A_m f_m\)) in phase modulation:

  1. Independent of the modulating signal frequency

    This is incorrect. The formula \(\Delta f_{max} = k_p A_m f_m\) shows that the frequency deviation is directly proportional to the modulating signal frequency \(f_m\).

  2. Inversely proportional to the square root of the modulating frequency

    This is incorrect. The frequency deviation is directly proportional to the modulating frequency \(f_m\), not inversely proportional to its square root.

  3. Inversely proportional to the modulating signal frequency

    This is incorrect. The frequency deviation is directly proportional to the modulating frequency \(f_m\), not inversely proportional.

  4. Directly proportional to the amplitude of the modulating signal

    This is correct. The formula \(\Delta f_{max} = k_p A_m f_m\) shows that the frequency deviation is directly proportional to the amplitude of the modulating signal \(A_m\), assuming \(k_p\) and \(f_m\) are constant.

Summary of Frequency Deviation in PM

In phase modulation, the peak frequency deviation is proportional to both the amplitude and the frequency of the modulating signal. This is a key characteristic that differentiates PM from FM, where the peak frequency deviation is only proportional to the amplitude of the modulating signal.

Revision Table: Comparing PM and FM Frequency Deviation

Feature Phase Modulation (PM) Frequency Modulation (FM)
Instantaneous Phase \(\theta_i(t)\) \(\omega_c t + k_p m(t)\) \(\omega_c t + k_f \int m(t) dt\)
Instantaneous Frequency \(\omega_i(t)\) \(\omega_c + k_p \frac{dm(t)}{dt}\) \(\omega_c + k_f m(t)\)
Frequency Deviation \(\Delta f(t)\) \(\frac{k_p}{2\pi} \frac{dm(t)}{dt}\) \(\frac{k_f}{2\pi} m(t)\)
Peak Frequency Deviation (for \(m(t)=A_m\cos(\omega_m t)\)) \(\Delta f_{max} = k_p A_m f_m\) \(\Delta f_{max} = \frac{k_f}{2\pi} A_m\)
Dependency of \(\Delta f_{max}\) on Modulating Signal Proportional to both Amplitude (\(A_m\)) and Frequency (\(f_m\)) Proportional only to Amplitude (\(A_m\))

Additional Information: Types of Angle Modulation

Angle modulation encompasses both Frequency Modulation (FM) and Phase Modulation (PM). The key difference lies in how the modulating signal affects the carrier's angle (phase).

  • Frequency Modulation (FM): The instantaneous frequency of the carrier is varied linearly with the instantaneous amplitude of the modulating signal. This is commonly used in broadcasting (like FM radio) due to its noise immunity.
  • Phase Modulation (PM): The instantaneous phase of the carrier is varied linearly with the instantaneous amplitude of the modulating signal. While less common for broadcasting than FM, PM is widely used in digital modulation schemes (like PSK - Phase Shift Keying) and in various communication systems. PM can be generated from FM signals using an integrator before the modulator, and FM can be generated from PM signals using a differentiator before the modulator.

Understanding the relationship between frequency deviation and modulating signal parameters is crucial for analyzing and designing angle modulation systems.

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Important Questions from Phase Modulation

  1. Which of the following phase modulation applications is INCORRECT?

  2. A message signal m(t) = A msin (2πf mt) is used to modulate the phase of a carrier A ccos (2πf ct) to get the modulated signal y(t) = A ccos (2πf ct + m(t)). The bandwidth of y(t)

  3. If the modulating signal is a constant DC voltage, the output of a Phase Modulator will be:

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