In phase modulation, frequency deviation is-
Directly proportional to the amplitude of the modulating signal
Phase modulation (PM) is a type of angle modulation where the phase of a carrier signal is varied in proportion to the instantaneous amplitude of the modulating signal. Unlike frequency modulation (FM), where the instantaneous frequency is directly proportional to the modulating signal's amplitude, in PM, it's the phase that is directly modulated.
Let the unmodulated carrier signal be represented as:
\(c(t) = A_c \cos(\omega_c t + \phi_c)\)
Where:
Let the modulating signal be \(m(t)\). In phase modulation, the instantaneous phase \(\theta_i(t)\) of the modulated signal is given by:
\(\theta_i(t) = \omega_c t + \phi_c + k_p m(t)\)
Where \(k_p\) is the phase sensitivity of the modulator (in radians/Volt or radians/Unit of \(m(t)\)). The PM signal is then:
\(s_{PM}(t) = A_c \cos(\theta_i(t)) = A_c \cos(\omega_c t + \phi_c + k_p m(t))\)
The instantaneous angular frequency \(\omega_i(t)\) of any angle-modulated signal is the time derivative of its instantaneous phase \(\theta_i(t)\). For PM, we have:
\(\omega_i(t) = \frac{d\theta_i(t)}{dt} = \frac{d}{dt}(\omega_c t + \phi_c + k_p m(t))\)
\(\omega_i(t) = \omega_c + k_p \frac{dm(t)}{dt}\)
The instantaneous frequency \(f_i(t) = \frac{\omega_i(t)}{2\pi}\) is:
\(f_i(t) = \frac{\omega_c}{2\pi} + \frac{k_p}{2\pi} \frac{dm(t)}{dt} = f_c + \frac{k_p}{2\pi} \frac{dm(t)}{dt}\)
The instantaneous frequency deviation \(\Delta f(t)\) from the carrier frequency \(f_c\) is the difference between the instantaneous frequency and the carrier frequency:
\(\Delta f(t) = f_i(t) - f_c = \frac{k_p}{2\pi} \frac{dm(t)}{dt}\)
This formula shows that the frequency deviation in phase modulation is proportional to the derivative of the modulating signal, not the signal itself.
Let's consider a single-tone modulating signal \(m(t) = A_m \cos(\omega_m t)\), where \(A_m\) is the amplitude and \(\omega_m = 2\pi f_m\) is the angular frequency of the modulating signal. The derivative of the modulating signal is:
\(\frac{dm(t)}{dt} = \frac{d}{dt}(A_m \cos(\omega_m t)) = -A_m \omega_m \sin(\omega_m t)\)
Substituting this into the frequency deviation formula:
\(\Delta f(t) = \frac{k_p}{2\pi} (-A_m \omega_m \sin(\omega_m t))\)
The maximum frequency deviation, often simply referred to as the frequency deviation (\(\Delta f_{max}\)), is the peak value of \(|\Delta f(t)|\). This occurs when \(|\sin(\omega_m t)| = 1\):
\(\Delta f_{max} = \frac{k_p}{2\pi} A_m \omega_m = \frac{k_p}{2\pi} A_m (2\pi f_m) = k_p A_m f_m\)
From this formula, we can clearly see the dependencies of the maximum frequency deviation in phase modulation:
Let's evaluate each provided option based on our derivation of the frequency deviation (\(\Delta f_{max} = k_p A_m f_m\)) in phase modulation:
Independent of the modulating signal frequency
This is incorrect. The formula \(\Delta f_{max} = k_p A_m f_m\) shows that the frequency deviation is directly proportional to the modulating signal frequency \(f_m\).
Inversely proportional to the square root of the modulating frequency
This is incorrect. The frequency deviation is directly proportional to the modulating frequency \(f_m\), not inversely proportional to its square root.
Inversely proportional to the modulating signal frequency
This is incorrect. The frequency deviation is directly proportional to the modulating frequency \(f_m\), not inversely proportional.
Directly proportional to the amplitude of the modulating signal
This is correct. The formula \(\Delta f_{max} = k_p A_m f_m\) shows that the frequency deviation is directly proportional to the amplitude of the modulating signal \(A_m\), assuming \(k_p\) and \(f_m\) are constant.
In phase modulation, the peak frequency deviation is proportional to both the amplitude and the frequency of the modulating signal. This is a key characteristic that differentiates PM from FM, where the peak frequency deviation is only proportional to the amplitude of the modulating signal.
| Feature | Phase Modulation (PM) | Frequency Modulation (FM) |
|---|---|---|
| Instantaneous Phase \(\theta_i(t)\) | \(\omega_c t + k_p m(t)\) | \(\omega_c t + k_f \int m(t) dt\) |
| Instantaneous Frequency \(\omega_i(t)\) | \(\omega_c + k_p \frac{dm(t)}{dt}\) | \(\omega_c + k_f m(t)\) |
| Frequency Deviation \(\Delta f(t)\) | \(\frac{k_p}{2\pi} \frac{dm(t)}{dt}\) | \(\frac{k_f}{2\pi} m(t)\) |
| Peak Frequency Deviation (for \(m(t)=A_m\cos(\omega_m t)\)) | \(\Delta f_{max} = k_p A_m f_m\) | \(\Delta f_{max} = \frac{k_f}{2\pi} A_m\) |
| Dependency of \(\Delta f_{max}\) on Modulating Signal | Proportional to both Amplitude (\(A_m\)) and Frequency (\(f_m\)) | Proportional only to Amplitude (\(A_m\)) |
Angle modulation encompasses both Frequency Modulation (FM) and Phase Modulation (PM). The key difference lies in how the modulating signal affects the carrier's angle (phase).
Understanding the relationship between frequency deviation and modulating signal parameters is crucial for analyzing and designing angle modulation systems.
Which of the following phase modulation applications is INCORRECT?
A message signal m(t) = A msin (2πf mt) is used to modulate the phase of a carrier A ccos (2πf ct) to get the modulated signal y(t) = A ccos (2πf ct + m(t)). The bandwidth of y(t)
If the modulating signal is a constant DC voltage, the output of a Phase Modulator will be: