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Question

In an ideal vapour compression refrigeration cycle, the specific enthalpy of refrigerant (kJ/kg) at the following stages is given as

Inlet of condenser = 283

Outlet of condenser = 116

Exit of evaporator = 232

The COP is

The correct answer is

2.27

Throttling preserves enthalpy, so \(h_4=h_3=116\ \mathrm{kJ/kg}\). The refrigerating effect is \(232-116=116\ \mathrm{kJ/kg}\) and compressor work is \(283-232=51\ \mathrm{kJ/kg}\).

\(\mathrm{COP}=\frac{116}{51}\approx2.27\)

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Important Questions from Refrigeration Cycles and Devices

  1. The refrigeration plants are charged by refrigerants from the cylinder at the _____.

  2. In actual refrigeration systems, the compressor handles vapours only. What is this process commonly referred to as?

  3. The condensing temperature in a refrigerator is the temperature _____.

  4. In a vapour compression refrigeration system, liquid to the suction heat exchanger is used to

  5. A hermetically sealed unit implies ____.

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