All Exams Test series for 1 year @ ₹349 only
Question

In an ideal vapor-compression refrigeration cycle, the specific enthalpy of refrigerant (in kJ/kg) at the following states is given as:

Inlet of condenser: 283

Exit of condenser: 116

Exit of evaporator: 232

The COP of this cycle is

The correct answer is

2.27

Throttling preserves enthalpy, so evaporator-inlet enthalpy is 116 kJ/kg. Refrigeration effect is 232−116=116 and compressor work 283−232=51 kJ/kg. COP=116/51=2.27.

Was this answer helpful?

Important Questions from Vapour Compression (V-C) Cycle

  1. A refrigeration plant works on an ideal vapour-compression refrigeration cycle with refrigerant as R-12 and develops a refrigeration capacity of 10 TR. If the refrigeration effect produced is 100 kJ/kg, what will be the mass flow rate of the refrigerant? [Assuming, 1 TR = 3.5 kW]

  2. In vapour compression refrigeration system, the effect of liquid refrigerant under cooling is to

  3. If vapour is NOT superheated after compression, it is called ________.

  4. The amount of heat removed in the evaporator per unit mass flow of refrigerant is called:

  5. In a vapor compression system, the highest temperature of the refrigerant during the cycle occurs after

Need Expert Advice?

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App