This problem involves calculating the final ratio of copper to zinc in a new alloy (Alloy C) formed by mixing equal amounts of two different alloys (Alloy A and Alloy B), each having a specific ratio of copper to zinc.
First, let's identify the composition of the initial alloys:
We are mixing equal parts of Alloy A and Alloy B to create Alloy C. To make the calculation straightforward, let's find a common basis for the parts. The total parts in Alloy A are 7, and in Alloy B are 14. The least common multiple (LCM) of 7 and 14 is 14.
Let's assume we take 14 units of Alloy A and 14 units of Alloy B. This ensures we are mixing equal quantities.
Now, we mix these amounts to form the new Alloy C:
Therefore, the ratio of copper to zinc in the new Alloy C is the ratio of the total copper to the total zinc:
$ \text{Ratio in Alloy C} = \text{Total Copper} : \text{Total Zinc} = 17:11 $In a 90 litre solution, acid and water are in the ratio 2 ∶ 1, To make the ratio of acid and water as 1 ∶ 2, how many litre of water should be added to the solution?
In a milk and water solution, the ratio of milk to water is 1 : 4. M litres of milk is added in it and ratio become 1 : 3. Again N litres of water is added in it and ratio become 2 : 7. If N – M = 4, then what is the initial quantity of solution?
A mixture contains acid and alcohol in the ratio of 3 : 2. On adding 10 litres of alcohol in mixture, the ratio of acid to alcohol becomes 3 : 5. The quantity of acid (in litres) in the original mixture was:
How many litres of acid are there in 12 litres of a 20% solution?
A mixture of fog contains water and air in the ratio 5 ∶ 3. On adding 8 liters of air, the ratio of water and air becomes 1 ∶ 1. The quantity of water in the original fog is: