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Question

In alloys A and B, copper and zinc are present in the ratio 4:3 and 9 : 5 respectively. If equal parts of both alloys are mixed to form a new alloy C, what will be the ratio of copper to zinc in alloy C?

The correct answer is
17:11

Ratio of Copper to Zinc in New Alloy C

This problem involves calculating the final ratio of copper to zinc in a new alloy (Alloy C) formed by mixing equal amounts of two different alloys (Alloy A and Alloy B), each having a specific ratio of copper to zinc.

Understanding the Ratios

First, let's identify the composition of the initial alloys:

  • Alloy A: Contains copper and zinc in the ratio 4:3. This means for every 4 parts of copper, there are 3 parts of zinc. The total number of parts in Alloy A is $4 + 3 = 7$.
  • Alloy B: Contains copper and zinc in the ratio 9:5. This means for every 9 parts of copper, there are 5 parts of zinc. The total number of parts in Alloy B is $9 + 5 = 14$.

Mixing Equal Parts of Alloys

We are mixing equal parts of Alloy A and Alloy B to create Alloy C. To make the calculation straightforward, let's find a common basis for the parts. The total parts in Alloy A are 7, and in Alloy B are 14. The least common multiple (LCM) of 7 and 14 is 14.

Let's assume we take 14 units of Alloy A and 14 units of Alloy B. This ensures we are mixing equal quantities.

Composition of Alloy A (14 units)

  • Amount of Copper in 14 units of Alloy A = $ \frac{4}{7} \times 14 \text{ units} = 8 \text{ units} $
  • Amount of Zinc in 14 units of Alloy A = $ \frac{3}{7} \times 14 \text{ units} = 6 \text{ units} $

Composition of Alloy B (14 units)

  • Amount of Copper in 14 units of Alloy B = $ \frac{9}{14} \times 14 \text{ units} = 9 \text{ units} $
  • Amount of Zinc in 14 units of Alloy B = $ \frac{5}{14} \times 14 \text{ units} = 5 \text{ units} $

Calculating the Ratio in Alloy C

Now, we mix these amounts to form the new Alloy C:

  • Total Copper in Alloy C: Sum of copper from Alloy A and Alloy B. $ \text{Total Copper} = 8 \text{ units} + 9 \text{ units} = 17 \text{ units} $
  • Total Zinc in Alloy C: Sum of zinc from Alloy A and Alloy B. $ \text{Total Zinc} = 6 \text{ units} + 5 \text{ units} = 11 \text{ units} $

Therefore, the ratio of copper to zinc in the new Alloy C is the ratio of the total copper to the total zinc:

$ \text{Ratio in Alloy C} = \text{Total Copper} : \text{Total Zinc} = 17:11 $
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Important Questions from To Make a Mixture from Two Mixtures

  1. In a 90 litre solution, acid and water are in the ratio 2 ∶ 1, To make the ratio of acid and water as 1 ∶ 2, how many litre of water should be added to the solution?

  2. In a milk and water solution, the ratio of milk to water is 1 : 4. M litres of milk is added in it and ratio become 1 : 3. Again N litres of water is added in it and ratio become 2 : 7. If N – M = 4, then what is the initial quantity of solution?

  3. A mixture contains acid and alcohol in the ratio of 3 : 2. On adding 10 litres of alcohol in mixture, the ratio of acid to alcohol becomes 3 : 5. The quantity of acid (in litres) in the original mixture was:

  4. How many litres of acid are there in 12 litres of a 20% solution?

  5. A mixture of fog contains water and air in the ratio 5 ∶ 3. On adding 8 liters of air, the ratio of water and air becomes 1 ∶ 1. The quantity of water in the original fog is: 

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