This problem involves calculating the final ratio of copper to zinc in a new alloy (Alloy C) formed by mixing equal amounts of two different alloys (Alloy A and Alloy B), each having a specific ratio of copper to zinc.
First, let's identify the composition of the initial alloys:
We are mixing equal parts of Alloy A and Alloy B to create Alloy C. To make the calculation straightforward, let's find a common basis for the parts. The total parts in Alloy A are 7, and in Alloy B are 14. The least common multiple (LCM) of 7 and 14 is 14.
Let's assume we take 14 units of Alloy A and 14 units of Alloy B. This ensures we are mixing equal quantities.
Now, we mix these amounts to form the new Alloy C:
Therefore, the ratio of copper to zinc in the new Alloy C is the ratio of the total copper to the total zinc:
$ \text{Ratio in Alloy C} = \text{Total Copper} : \text{Total Zinc} = 17:11 $One cup has juice and water in the ratio 5 ∶ 2, while another cup of the same capacity has them in the ratio 7 ∶ 4, respectively. If contents of both the cups (when full) are poured in a vessel, then what will be the final ratio of water to juice in the vessel?
A and B are solutions of acid and water. The ratios of water and acid in A and B are 4 : 5 and 1 : 2 respectively. If x liters of A is mixed with y liters of B, then the ratio of water and acid in the mixture becomes 8 : 13 What is x : y?
A drink of chocolate and milk contains 8% pure chocolate by volume. If 10 litres of pure milk are added to 50 litres of this drink, the percentage of chocolate in the new drink is:
Mixture A contains chocolate and milk in the ratio 4 ∶ 3 and mixture B contains chocolate and milk in the ratio 5 ∶ 2. A and B are taken in the ratio 5 ∶ 6 and mixed to form a new mixture. The percentage of chocolate in the new mixture is closest to:
If 80 litres of milk solution has 60% milk in it, then how much milk should be added to make milk 80% in the solution?