In a vernier calliper, the main scale reads in millimetres with a least count of 0.1 mm. Ten divisions on the vernier correspond to nine divisions of the main scale. Determine the least count of the calliper.
0.01 mm
A vernier caliper is a precision instrument used for measuring lengths, depths, and external or internal diameters. Its accuracy is determined by its least count, which is the smallest measurement that can be made reliably with the instrument.
The least count of a vernier caliper depends on the main scale least count and the relationship between the divisions on the main scale and the vernier scale.
The problem provides the following information:
Let's denote the value of one main scale division as MSD and the value of one vernier scale division as VSD.
From the given information:
We can find the value of one vernier scale division (VSD):
\(10 \times \text{VSD} = 9 \times \text{MSD}\)
\(\text{VSD} = \frac{9}{10} \times \text{MSD}\)
\(\text{VSD} = \frac{9}{10} \times 0.1 \, \text{mm}\)
\(\text{VSD} = 0.9 \times 0.1 \, \text{mm}\)
\(\text{VSD} = 0.09 \, \text{mm}\)
The least count (LC) of a vernier caliper is defined as the difference between the value of one main scale division and the value of one vernier scale division.
The formula for the least count is:
\(\text{LC} = \text{MSLC} - \text{VSD}\)
Alternatively, using the relationship between the scales:
If N vernier scale divisions match (N-1) main scale divisions, then:
\(\text{N} \times \text{VSD} = (N-1) \times \text{MSD}\)
\(\text{VSD} = \frac{N-1}{N} \times \text{MSD}\)
Since MSLC = MSD,
\(\text{LC} = \text{MSLC} - \text{VSD} = \text{MSLC} - \frac{N-1}{N} \times \text{MSLC}\)
\(\text{LC} = \text{MSLC} \times \left(1 - \frac{N-1}{N}\right) = \text{MSLC} \times \left(\frac{N - (N-1)}{N}\right) = \text{MSLC} \times \frac{1}{N}\)
So, the least count can also be calculated as:
\(\text{LC} = \frac{\text{MSLC}}{N}\)
Using the given values:
\(\text{LC} = \frac{0.1 \, \text{mm}}{10}\)
\(\text{LC} = 0.01 \, \text{mm}\)
This result matches the difference method as well:
\(\text{LC} = \text{MSLC} - \text{VSD} = 0.1 \, \text{mm} - 0.09 \, \text{mm} = 0.01 \, \text{mm}\)
Therefore, the least count of the vernier caliper is 0.01 mm.
| Parameter | Value |
|---|---|
| Main Scale Least Count (MSLC) | 0.1 mm |
| Number of Vernier Divisions (N) | 10 |
| Relation | 10 VSD = 9 MSD |
| Calculated VSD | 0.09 mm |
| Calculated Least Count (LC) | 0.01 mm |
| Concept | Description | Formula (if applicable) |
|---|---|---|
| Main Scale Least Count (MSLC) | Smallest division value on the main scale. | Given or determined from main scale markings. |
| Vernier Scale Division (VSD) | Value of one division on the vernier scale. | Calculated from the relationship with MSD/MSLC. |
| Least Count (LC) of Vernier Caliper | Smallest measurement discernible by the instrument. | \(\text{LC} = \text{MSLC} - \text{VSD}\) OR \(\text{LC} = \frac{\text{MSLC}}{N}\) |
| Zero Error | Reading when the jaws are closed. Needs to be subtracted (if positive) or added (if negative) to the observed reading. | — |
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