In a three-phase supply, Vbn = 110 ∠30° V. Assuming a positive sequence, find Vcn .
In a three-phase AC supply system, three distinct AC voltages are used. These voltages are balanced, meaning they share the same magnitude, and are phase-shifted from each other by 120 degrees.
A positive sequence signifies a particular order for these phases, conventionally A -> B -> C. This sequence establishes a fixed phase relationship between the voltages:
Vbn) lags behind the voltage of phase A (Van) by 120 degrees.Vcn) lags behind the voltage of phase B (Vbn) by 120 degrees.Vcn lags Van by 240 degrees, which is equivalent to leading by 120 degrees.The relationship connecting consecutive phases in a positive sequence is expressed as:
Vcn = Vbn ∠ -120°
The problem provides the voltage for phase B:
Vbn = 110 ∠30° V
To determine the voltage for phase C (Vcn) under the assumption of a positive sequence, we apply the established relationship:
Vcn = Vbn ∠ -120°
Substitute the given value of Vbn into this equation:
Vcn = (110 ∠30°) ∠ -120° V
To compute the resultant phasor voltage, we sum the phase angles:
Vcn = 110 ∠(30° - 120°) V
Performing the angle subtraction:
Vcn = 110 ∠-90° V
The calculation yields 110 ∠-90° V for the phase voltage Vcn.
We now compare this result with the multiple-choice options provided:
| Option Number | Voltage Value | Verification |
|---|---|---|
| 1 | 110 ∠-90° V |
Matches Calculation |
| 2 | 110 ∠-30° V |
Does not match |
| 3 | 110 ∠150° V |
Does not match |
| 4 | 110 ∠120° V |
Does not match |
The calculation confirms that 110 ∠-90° V is the correct voltage for Vcn when considering a positive sequence three-phase supply with the given Vbn.
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