Tension Member Failure Factors
When rivet holes in a tension member are misaligned (off the line), the member's failure is influenced by several geometric factors related to the riveting pattern and hole size.
Understanding Failure Influence
The failure of a tension member with off-line rivet holes depends on how the stress is distributed around these holes and the resulting net effective area. Key factors include:
- Pitch: The distance between the centers of two consecutive rivets measured along the direction of the load. Variations in pitch can affect the shear lag and stress concentration.
- Gauge: The distance between the lines of centers of two adjacent rows of rivets, measured perpendicular to the direction of the load. Incorrect gauge distance can lead to uneven stress distribution across the member's width.
- Diameter of the rivet holes: The size of the holes directly reduces the net cross-sectional area available to carry the tensile load. Larger holes mean less area and higher stress concentration around the hole edges, increasing the likelihood of failure.
Since pitch, gauge, and the diameter of the rivet holes all play a role in determining the stress distribution and the effective area of the member, they collectively influence the failure point.
Therefore, the failure depends upon All of these factors.
Important Questions from Tension Member
The following are the statements about lug angle used to connect heavily loaded tension member to gusset plates.
(i) The length of end connection is reduced
(ii) By using lug angles there will be saving in the gusset plate
(iii) Cost of connection increases due to additional fasteners and angle required.
A structural member subjected to tensile force in a direction parallel to its longitudinal axis is generally known as
When the length of a tension member is too long:
The allowable stress in axial tension is generally kept less if the thickness of the member is more than
A single angle in tension is connected by one leg only. If the areas of connecting and outstanding legs are respectively a and b, then what is the net effective area of the angle?
A) \(a-\frac{b}{1+0.35\times\frac{b}{a}}\)
B) \(a+\frac{b}{1+0.35\times\frac{b}{a}}\)
C) \(a-\frac{b}{1+0.20\times\frac{b}{a}}\)
D) \(a+\frac{b}{1+0.20\times\frac{b}{a}}\)
