In a survey where 100 students reported which subjects they like, 32 students in total liked Mathematics, 38 students liked Business and 30 students liked Literature. Moreover 7 students liked both Mathematics and Literature, 10 students liked both Mathematics and Business, 8 students liked both Business and Literature, 5 students liked all three subjects. Then the number of people who liked exactly one subject is
65
This question involves analyzing survey data about student preferences for three subjects: Mathematics, Business, and Literature. We need to determine how many students liked exactly one of these subjects.
We are given the following information from a survey of 100 students:
To find the number of students who liked exactly one subject, we first need to determine the number of students in each specific overlap category using the provided data. We can use the principle of inclusion-exclusion or visualize this with a Venn diagram.
The number of students who liked all three subjects is given:
Now, let's find the number of students who liked exactly two subjects:
With the overlap calculations done, we can now find the number of students who liked only one subject. This is done by taking the total number of students who liked a subject and subtracting those who liked it in combination with other subjects.
Number of students who liked only Mathematics:
$|M \text{ only}| = |M| - (|M \cap B \text{ only}| + |M \cap L \text{ only}| + |M \cap B \cap L|)$
$|M \text{ only}| = 32 - (5 + 2 + 5) = 32 - 12 = 20$
Number of students who liked only Business:
$|B \text{ only}| = |B| - (|M \cap B \text{ only}| + |B \cap L \text{ only}| + |M \cap B \cap L|)$
$|B \text{ only}| = 38 - (5 + 3 + 5) = 38 - 13 = 25$
Number of students who liked only Literature:
$|L \text{ only}| = |L| - (|M \cap L \text{ only}| + |B \cap L \text{ only}| + |M \cap B \cap L|)$
$|L \text{ only}| = 30 - (2 + 3 + 5) = 30 - 10 = 20$
Finally, to find the total number of students who liked exactly one subject, we sum the numbers calculated for each subject individually:
Total = (Mathematics only) + (Business only) + (Literature only)
Total = $20 + 25 + 20 = 65$
Therefore, 65 students liked exactly one subject.
| Subject Combination | Calculation | Count |
|---|---|---|
| Mathematics & Business & Literature | Given | 5 |
| Mathematics & Business only | $|M \cap B| - |M \cap B \cap L|$ | $10 - 5 = 5$ |
| Business & Literature only | $|B \cap L| - |M \cap B \cap L|$ | $8 - 5 = 3$ |
| Mathematics & Literature only | $|M \cap L| - |M \cap B \cap L|$ | $7 - 5 = 2$ |
| Mathematics only | $|M| - (\text{M&B only}) - (\text{M&L only}) - (\text{All three})$ | $32 - 5 - 2 - 5 = 20$ |
| Business only | $|B| - (\text{M&B only}) - (\text{B&L only}) - (\text{All three})$ | $38 - 5 - 3 - 5 = 25$ |
| Literature only | $|L| - (\text{M&L only}) - (\text{B&L only}) - (\text{All three})$ | $30 - 2 - 3 - 5 = 20$ |
| Total Exactly One Subject | Sum of 'only' counts | $20 + 25 + 20 = 65$ |
Match List I with List II
Let R 1= {(1, 1), (2, 2), (3, 3)} and R 2 = {(1, 1), (1, 2), (1, 3), (1, 4)}
List I | List II |
(A) R 1∪ R 2 | (I) {(1, 1), (1, 2), (1, 3), (1, 4), (2, 2), (3, 3)} |
(B) R 1- R 2 | (II) {1, 1} |
(C) R 1∩ R 2 | (III) {(1, 2), (1, 3), (1, 4)} |
(D) R 2- R 1 | (IV) {(2, 2), (3, 3)} |
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