Calculating Attitude Statement Pairs
The question asks for the total number of unique pairs that can be formed from eleven distinct attitude statements. This is a problem of combinations, as the order of statements in a pair does not matter (e.g., pair A-B is the same as pair B-A).
We need to find the number of ways to choose 2 statements from a set of 11. The formula for combinations is:
$ \binom{n}{k} = \frac{n!}{k!(n-k)!} $
Where:
- $n$ is the total number of items (statements) = 11
- $k$ is the number of items to choose for each combination (pair) = 2
Combination Calculation
Applying the formula:
$ \binom{11}{2} = \frac{11!}{2!(11-2)!} $
$ \binom{11}{2} = \frac{11!}{2!9!} $
$ \binom{11}{2} = \frac{11 \times 10 \times 9!}{ (2 \times 1) \times 9!} $
Cancel out $9!$:
$ \binom{11}{2} = \frac{11 \times 10}{2} $
$ \binom{11}{2} = \frac{110}{2} $
$ \binom{11}{2} = 55 $
Therefore, there are 55 possible pairs of attitude statements.
Important Questions from Measurement and Analysis of Data - Teaching
- Identify the variables that pertain to interval scale of measurement
A. gender
B. date of birth of a person
C. religion
D. time of the day
Choose the correct answer from the options given below: - F-ratio is
- Which statements of the following are true about Spearman-Brown prophecy formula?
A. In the split half method, the reliability coefficient of the whole test can be estimated with the help of
reliability coefficient of the half test by using this formula.
B. This formula may be used to estimate the reliability of ratings as well as test scores.
C. It cannot be used to estimate the reliability of paired comparisons.
D. It cannot be used to obtain the effect on reliability by lengthening or repeating a test.
Choose the correct answer from the options given below: - Which of the following is NOT true about errors in measurement?
- In a two-tailed test, for a particular degree of freedom, if a null hypothesis could not be rejected at 0.01 level of significance, then at 0.05 level of significance, this null hypothesis
