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Question

In a single slit diffraction pattern, how does the angular width of the central maximum change with the increasing slit width?
10

The correct answer is
It will decrease.

Understanding Single Slit Diffraction

Single slit diffraction is a phenomenon observed when light passes through a narrow opening (slit). Instead of projecting a sharp shadow of the slit, a pattern of bright and dark bands, called fringes, appears on a screen placed behind the slit. The brightest fringe is located at the center and is known as the central maximum.

Analyzing Central Maximum Width vs. Slit Width

In the single-slit diffraction pattern, the bright fringes are separated by dark fringes called minima. The position of these minima is determined by the slit width ($a$), the wavelength of light ($\lambda$), and the angle of diffraction ($\theta$).

The condition for the first minimum (the dark band on either side of the central maximum) is given by the formula:

$$a \sin(\theta) = \lambda$$

Where:

  • $a$ = width of the slit
  • $\theta$ = angle of diffraction for the first minimum
  • $\lambda$ = wavelength of the light

For small angles, which is common in diffraction experiments, we can approximate $\sin(\theta) \approx \theta$ (where $\theta$ is in radians). Thus, the equation becomes:

$$a \theta \approx \lambda$$

This gives us the angle for the first minimum:

$$\theta \approx \frac{\lambda}{a}$$

The central maximum extends from the first minimum on one side ($-\theta$) to the first minimum on the other side ($+\theta$). Therefore, the total angular width ($\Delta \theta$) of the central maximum is:

$$\Delta \theta = \theta - (-\theta) = 2\theta$$

Substituting the expression for $\theta$:

$$\Delta \theta \approx \frac{2\lambda}{a}$$

From this equation, we can see that the angular width of the central maximum ($\Delta \theta$) is inversely proportional to the slit width ($a$).

Conclusion on Changing Slit Width

Based on the relationship $\Delta \theta \propto \frac{1}{a}$:

  • If the slit width ($a$) increases, the denominator in the fraction $\frac{2\lambda}{a}$ gets larger.
  • This causes the value of $\Delta \theta$ to become smaller.

Therefore, as the slit width increases, the angular width of the central maximum decreases. The central bright spot becomes narrower.

The correct option is that it will decrease.

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Important Questions from Diffraction

  1. In the dispersion of white light by a common glass prism, which one among the following is correct?

  2. In a double-slit experiment, when light of wavelength $\text{600 nm}$ is used, the central maximum and the second bright fringe are separated by $\text{3 mm}$ on a screen placed $\text{1.5 m}$ away. If the entire apparatus is then immersed in a liquid with a refractive index of $\text{1.5}$, what will be the angular separation between the first and fourth dark fringes?

  3. Which one of the following statements about X-rays is not true?

  4. When light passes from air to water, the angle of refraction is:

  5. The primary rainbow appears after the rain is due to

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