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Question

In a single degree of freedom vibrating system with only viscous damping, the critical damping coefficient is 350 N s/m and the damping coefficient is 35 N s/m. 

The logarithmic decrement of the vibrating system is

The correct answer is
0.63

Calculating Logarithmic Decrement

The logarithmic decrement ($\delta$) quantifies the rate at which free vibrations decay in a damped system. It is directly related to the damping characteristics of the system, specifically the damping ratio ($\zeta$).

Determining the Damping Ratio

First, we find the damping ratio ($\zeta$) using the given damping coefficient ($c$) and critical damping coefficient ($c_c$).

Given values:

  • Actual damping coefficient: $c = 35 \text{ N s/m}$
  • Critical damping coefficient: $c_c = 350 \text{ N s/m}$

The damping ratio is calculated as:

$ \zeta = \frac{c}{c_c} $ $ \zeta = \frac{35 \text{ N s/m}}{350 \text{ N s/m}} $ $ \zeta = 0.1 $

Calculating Logarithmic Decrement

The logarithmic decrement ($\delta$) is related to the damping ratio ($\zeta$) by the formula:

$ \delta = \frac{2 \pi \zeta}{\sqrt{1 - \zeta^2}} $

Substitute the calculated damping ratio ($\zeta = 0.1$) into the formula:

$ \delta = \frac{2 \pi (0.1)}{\sqrt{1 - (0.1)^2}} $ $ \delta = \frac{0.2 \pi}{\sqrt{1 - 0.01}} $ $ \delta = \frac{0.2 \pi}{\sqrt{0.99}} $ $ \delta \approx \frac{2 \times 3.14159 \times 0.1}{0.994987} $ $ \delta \approx \frac{0.628318}{0.994987} $ $ \delta \approx 0.6315 $

Rounding to two decimal places, the logarithmic decrement is approximately 0.63.

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Important Questions from Damping Coefficient and Damping Ratio

  1. 6ẍ + 9ẋ + 27x = 0 is the equation of motion for a damped vibration. The damping factor shall be:
  2. Ratio of actual to critical damping coefficient in forced vibrations is known as ________.
  3. ______ is defined as the ratio of the actual damping coefficient to a critical damping coefficient.

  4. A spring-mass-damper system having single degree of freedom has a spring with strength 25 kN/m, mass 0.1 kg and coefficient of damping 40 N-s/m. The damping factor of the system will be

  5. The damping ratio for a viscously damped spring mass system, governed by the relationship is \(m\frac{{{d^2}x}}{{d{t^2}}} + c\frac{{dx}}{{dt}} + kx = F\) given by

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