In a school, periodical examinations are held every two months. During the academic session from April 2001 to March 2002, a Class IX student appeared in each of these periodical exams. The line graph below shows the total marks obtained by the student in each periodical exam. Maximum Total Marks in each periodical exam = 500. 
What is the percentage of the marks obtained by the student in the periodical exams of August 2001 and October 2001 combined?
The question requires us to find the percentage of marks obtained by the student in the periodical exams of August 2001 and October 2001 combined.
From the line graph provided, the total marks obtained are:
- August 2001: 370 marks
- October 2001: 385 marks
The combined marks for August 2001 and October 2001 are:
\(370 + 385 = 755\)
The maximum total marks for each exam are 500.
So, the maximum possible marks for both exams combined are \(2 \times 500 = 1000\).
To find the percentage of marks obtained out of this maximum, we use the formula:
\(\text{Percentage} = \left( \frac{\text{Obtained Marks}}{\text{Maximum Marks}} \right) \times 100\)
Substituting the values, we have:
\(\text{Percentage} = \left( \frac{755}{1000} \right) \times 100 = 75.5\%\)
Therefore, the percentage of the marks obtained by the student in the periodical exams of August 2001 and October 2001 combined is 75.50%.
Thus, the correct answer is 75.50%.
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