In a class of 60 students, 45 students like music, 50 students like dancing, 5 students like neither. Then the number of students in the class who like both music and dancing is
40
This problem involves finding the number of students who like both music and dancing, given the total number of students, those who like music, those who like dancing, and those who like neither. We can solve this using the principles of set theory or by visualizing it with a Venn diagram.
Let's break down the numbers provided in the question:
First, we can find the number of students who like at least one of the activities (music or dancing). These are the students who are not in the group that likes neither. The total number of students is the sum of students who like at least one activity and students who like neither.
Number of students liking at least one activity = Total students - Number of students liking neither
Number of students liking at least one activity = $\text{60} - \text{5} = \text{55}$
So, 55 students like either music, or dancing, or both music and dancing.
We can use the formula for the union of two sets. Let M be the set of students who like music, and D be the set of students who like dancing. The number of students who like at least one activity is the number of students in the union of sets M and D, denoted as $|M \cup D|$. The number of students who like both activities is the number of students in the intersection of sets M and D, denoted as $|M \cap D|$.
The principle of inclusion-exclusion for two sets states:
$|M \cup D| = |M| + |D| - |M \cap D|$
We know:
We want to find $|M \cap D|$, which is the number of students who like both music and dancing. Let's substitute the known values into the formula:
$\text{55} = \text{45} + \text{50} - |M \cap D|$
$\text{55} = \text{95} - |M \cap D|$
Now, we can rearrange the equation to solve for $|M \cap D|$:
$|M \cap D| = \text{95} - \text{55}$
$|M \cap D| = \text{40}$
Therefore, the number of students in the class who like both music and dancing is 40.
| Category | Number of Students |
|---|---|
| Total Students | 60 |
| Like Music ($|M|$) | 45 |
| Like Dancing ($|D|$) | 50 |
| Like Neither | 5 |
| Like At Least One ($|M \cup D|$) | 55 |
| Like Both ($|M \cap D|$) | 40 |
By using the information about the total students, those who like music, those who like dancing, and those who like neither, we calculated that 55 students like at least one activity. Applying the inclusion-exclusion principle, we found that 40 students like both music and dancing.
Here’s a quick look back at the key numbers and what they represent in this problem about students liking music and dancing.
| Term | Meaning | Value |
|---|---|---|
| Total Students | Entire class size | 60 |
| Like Music | Students in set M | 45 |
| Like Dancing | Students in set D | 50 |
| Like Neither | Students outside M and D | 5 |
| Like At Least One | Students in M or D or both ($|M \cup D|$) | 60 - 5 = 55 |
| Like Both | Students in M and D ($|M \cap D|$) | 45 + 50 - 55 = 40 |
Problems like this, dealing with groups of people or items that have overlapping characteristics, are commonly solved using set theory concepts. The total collection is often called the universal set (U). The subgroups are represented as sets (like M for Music, D for Dancing).
Key concepts used here:
Understanding these basic set theory principles is very helpful for solving problems involving surveys or data with overlapping categories.
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