In a class, 20 students opted for physics, 17 for Maths, 12 for both physics and maths and 10 students for other subjects. The class contains how many students?
35
To determine the total number of students in the class, we need to consider students who opted for Physics, those who opted for Maths, those who opted for both, and those who opted for other subjects. We will use the principle of inclusion-exclusion to find the unique count of students taking Physics or Maths, and then add the students taking other subjects.
The inclusion-exclusion principle helps us find the total number of unique students who opted for at least one of the two subjects (Physics or Maths). The formula for two sets is:
$\text{n(A} \cup \text{B)} = \text{n(A)} + \text{n(B)} - \text{n(A} \cap \text{B)}$
Here, A represents students opting for Physics and B represents students opting for Maths.
So, 25 students opted for either Physics or Maths (or both, counted once).
To find the total number of students in the class, we add the students who opted for Physics or Maths to the students who opted for other subjects.
| Category | Number of Students |
|---|---|
| Only Physics | $20 - 12 = 8$ |
| Only Maths | $17 - 12 = 5$ |
| Both Physics and Maths | 12 |
| Other Subjects | 10 |
| Total Class Students | $8 + 5 + 12 + 10 = 35$ |
Therefore, the class contains 35 students.
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The standard ordered basis of ℝ 2is {e 1, e 2}. Let T : ℝ 2 → ℝ 2 be the linear transformation such that T reflects the points through the line x 1= -x 2. The standard matrix of T is:
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