In a circuit, a 10-volt battery and three resistors ( R1 = 2 Ω ), ( R2 = 3 Ω), and ( R3 = 6 Ω) are connected in parallel to each other. Which of the following is the correct value of effective resistance ( Re ) and current I flowing through the circuit?
( Re = 1 Ω I = 10 A )
To find the effective resistance (Re) of resistors connected in parallel, we use the formula:
1/Re=1/R1+1/R2+1/R3
Substitute the given values (R1=2Ω, R2=3Ω, R3=6Ω):
1/Re=1/2+1/3+1/6
Calculate the right-hand side:
=3/6+2/6+1/6=6/6=1
Thus, Re=1 Ω.
Next, use Ohm's Law to find the current (I):
I=V/Re
Given the battery voltage V=10V and Re=1Ω, substitute these values into Ohm's Law:
I=10/1=10A
Thus, the effective resistance is Re=1 Ω, and the current flowing through the circuit is I=10 A.
Important Questions from Resistance and Resistivity
Which of the following statements are correct about the electrical resistance and resistivity of a wire?
1. Both quantities depend on the area of cross-section of the wire
2. Both depend on the temperature
3. Resistance of the wire is directly proportional to the resistivity of the wire
4. Resistivity of the wire is directly proportional to the length of the
wireSelect the correct answer using the code given below:
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