In a circuit, a 10-volt battery and three resistors ( R1 = 2 Ω ), ( R2 = 3 Ω), and ( R3 = 6 Ω) are connected in parallel to each other. Which of the following is the correct value of effective resistance ( Re ) and current I flowing through the circuit?
( Re = 1 Ω I = 10 A )
To find the effective resistance (Re) of resistors connected in parallel, we use the formula:
1/Re=1/R1+1/R2+1/R3
Substitute the given values (R1=2Ω, R2=3Ω, R3=6Ω):
1/Re=1/2+1/3+1/6
Calculate the right-hand side:
=3/6+2/6+1/6=6/6=1
Thus, Re=1 Ω.
Next, use Ohm's Law to find the current (I):
I=V/Re
Given the battery voltage V=10V and Re=1Ω, substitute these values into Ohm's Law:
I=10/1=10A
Thus, the effective resistance is Re=1 Ω, and the current flowing through the circuit is I=10 A.
Important Questions from Resistance and Resistivity
If the length of a conductor is doubled, then the resistance of the conductor will be: (other parameters are kept same)
Which factor does NOT affect the resistivity of a material?
Based on the English alphabetical order, three of the following four letter-clusters are alike in a certain way and thus form a group. Which letter-cluster does not belong to that group?
(Note: The odd one out is not based on the number of consonants/vowels or their position in the letter-cluster.)
A uniform wire of resistance 9Ω is bent in the form of an equilateral triangle. Find the effective resistance across a side of the triangle.
A potential difference of 10V is applied across a conductor of conductance 5Ω-1. The current through the conductor is :
