In a certain population, 22% of people are smokers, 57% of people are males and 12% males are smokers. If a person is chosen at random from the population, what is that probality that selected person is either a male or a smoker?
0.67
The question asks for the probability that a randomly selected person from a population is either a male or a smoker. This involves calculating the probability of the union of two events: being a male and being a smoker. We are given the individual probabilities of these events and the probability of a male being a smoker, which we will interpret as the probability of a person being both male and a smoker.
We are provided with the following information:
To find the probability that the selected person is either a male or a smoker, we use the formula for the probability of the union of two events A and B:
\(\text{P(A or B)} = \text{P(A)} + \text{P(B)} - \text{P(A and B)}\)
In this case, Event A is selecting a male, and Event B is selecting a smoker. So, we want to find P(Male or Smoker).
Using the formula and the given probabilities:
\(\text{P(Male or Smoker)} = \text{P(Male)} + \text{P(Smoker)} - \text{P(Male and Smoker)}\)
\(\text{P(Male or Smoker)} = 0.57 + 0.22 - 0.12\)
\(\text{P(Male or Smoker)} = 0.79 - 0.12\)
\(\text{P(Male or Smoker)} = 0.67\)
Thus, the probability that the selected person is either a male or a smoker is 0.67.
| Event | Probability |
|---|---|
| Smoker (S) | 0.22 |
| Male (M) | 0.57 |
| Male and Smoker (M and S) | 0.12 |
| Male or Smoker (M or S) | P(M) + P(S) - P(M and S) = 0.57 + 0.22 - 0.12 = 0.67 |
| Concept | Formula | Explanation |
|---|---|---|
| Probability of A or B (Union) | \(P(A \cup B) = P(A) + P(B) - P(A \cap B)\) | Used when finding the probability that at least one of two events occurs. Subtracts the intersection to avoid double-counting. |
| Probability of A and B (Intersection - Independent Events) | \(P(A \cap B) = P(A) \times P(B)\) | Used if events A and B are independent. |
| Probability of A and B (Intersection - Dependent Events) | \(P(A \cap B) = P(A|B) \times P(B) = P(B|A) \times P(A)\) | Used if events A and B are dependent. P(A|B) is the probability of A given B. |
| Conditional Probability | \(P(A|B) = \frac{P(A \cap B)}{P(B)}\) | The probability of event A occurring given that event B has already occurred. |
Probability is a measure of the likelihood that an event will occur. It is a value between 0 and 1, inclusive.
In this problem, being male and being a smoker are not mutually exclusive (as some males are smokers) and not independent (as the probability of being a smoker might be different for males and females, indicated by the provided P(Male and Smoker)). Therefore, the general formula for the union must be used.
Read the given figure and find the region representing persons who are educated and employed but not confirmed in job.

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