In a certain code language, 'PAR' is coded as ‘35' and 'GAT' is coded as ‘28'. How will 'FOM' be coded in that language?
34
The question asks us to decode a certain language pattern based on two examples: 'PAR' is coded as '35', and 'GAT' is coded as '28'. We need to apply this same logic to find the code for 'FOM'.
Let's analyze the given examples to find the underlying rule. A common method in coding-decoding problems is to look at the positional values of the letters in the English alphabet (A=1, B=2, ..., Z=26).
Let's find the positional values for each letter in 'PAR':
Now let's see if combining these values gives us 35. Let's try summing them up:
\( 16 + 1 + 18 = 35 \)
This matches the given code for 'PAR'. This suggests that the pattern might be the sum of the positional values of the letters.
Let's verify this pattern with the second example, 'GAT', which is coded as '28'.
Find the positional values for each letter in 'GAT':
Now, let's sum these values:
\( 7 + 1 + 20 = 28 \)
This also matches the given code for 'GAT'. The pattern seems to be consistently the sum of the positional values of the letters in the word.
Now we will apply the same pattern to find the code for 'FOM'.
Find the positional values for each letter in 'FOM':
Sum these positional values:
\( 6 + 15 + 13 \)
\( 6 + 15 = 21 \)
\( 21 + 13 = 34 \)
So, 'FOM' should be coded as 34.
| Word | Letters | Positional Values | Sum | Coded Value |
|---|---|---|---|---|
| PAR | P, A, R | 16, 1, 18 | 16 + 1 + 18 = 35 | 35 |
| GAT | G, A, T | 7, 1, 20 | 7 + 1 + 20 = 28 | 28 |
| FOM | F, O, M | 6, 15, 13 | 6 + 15 + 13 = 34 | 34 |
The coded value for 'FOM' is 34.
| Concept | Description | Relevance to Problem |
|---|---|---|
| Coding-Decoding | Problems where words/numbers are coded based on a specific rule, and the rule must be identified to decode a new word/number. | The core type of problem presented in the question. |
| Positional Values | Assigning a numerical value to each letter based on its position in the alphabet (A=1, B=2, ...). | The key method used to solve this specific coding pattern. |
| Pattern Recognition | Identifying the consistent rule or logic applied across the given examples. | Essential skill required to solve coding-decoding questions. |
Coding-decoding questions can use various patterns. Besides summing positional values, other common patterns include:
To solve coding-decoding problems, it's important to analyze the given examples carefully and test different potential patterns involving letter positions or other properties until a consistent rule is found.
A stone is thrown horizontally from the top of a 20 m high building with a speed of 12 m/s. It hits the ground at a distance R from the building. Taking g = 10 m/s2 and neglecting air resistance will give :
A sphere of volume V is made of a material with lower density than water. While on Earth, it floats on water with its volume f1V (f1 < 1) submerged. On the other hand, on a spaceship accelerating with acceleration a < g (g is the acceleration due to gravity on Earth) in outer space, its submerged volume in water is f2V. Then:
A railway wagon (open at the top) of mass M1 is moving with speed v1 along a straight track. As a result of rain, after some time it gets partially filled with water so that the mass of the wagon becomes M2 and speed becomes v2. Taking the rain to be falling vertically and the water stationery inside the wagon, the relation between the two speeds v1 and v2 is :
Consider the following statements:
1. Distance between the longitudes becomes zero on North Pole and South Pole.
2. Distance between the longitudes is maximum on the Equator.
3. Number of longitudes is more than number of latitudes.
Which of the statements given above is/are correct?
One block of 2⋅0 kg mass is placed on top of another block of 3⋅0 kg mass. The coefficient of static friction between the two blocks is 0⋅2. The bottom block is pulled with a horizontal force F such that both the blocks move together without slipping. Taking acceleration due to gravity as 10 m/s2, the maximum value of the frictional force is :