All Exams Test series for 1 year @ ₹349 only
Question

In a case-control study, 300 women aged 20-45 years suffering from breast cancer were compared with age-matched 300 women without breast cancer. It was observed that 120 women among cases and 60 women among controls were obese. The odds ratio of developing breast cancer among obese women is:

The correct answer is
8/3

Understanding Odds Ratio Calculation

This problem requires calculating the Odds Ratio (OR) from a case-control study. The OR estimates the odds of exposure (obesity) among cases (breast cancer patients) compared to the odds of exposure among controls (women without breast cancer).

Case-Control Study Data Setup

First, let's define the groups and exposure status:

  • Cases: Women with breast cancer (Total = 300)
  • Controls: Women without breast cancer (Total = 300)
  • Exposure: Obesity

Constructing the 2x2 Contingency Table

We can represent the data in a 2x2 table, where 'a' and 'c' represent the number of exposed individuals (obese) in cases and controls, respectively, and 'b' and 'd' represent the number of unexposed individuals (not obese) in cases and controls, respectively.

  • Number of obese cases (a) = 120
  • Number of obese controls (c) = 60
  • Number of non-obese cases (b) = Total cases - Obese cases = 300 - 120 = 180
  • Number of non-obese controls (d) = Total controls - Obese controls = 300 - 60 = 240

The table is structured as follows:

Obese (Exposed) Not Obese (Unexposed) Total
Breast Cancer (Cases) 120 (a) 180 (b) 300
No Breast Cancer (Controls) 60 (c) 240 (d) 300
Total 180 420 600

Calculating the Odds Ratio (OR)

The formula for the Odds Ratio in a case-control study is:

$ OR = \frac{\text{Odds of exposure in cases}}{\text{Odds of exposure in controls}} = \frac{a/b}{c/d} = \frac{ad}{bc} $

Substitute the values from the table:

$ OR = \frac{120 \times 240}{180 \times 60} $

Now, simplify the calculation:

$ OR = \frac{28800}{10800} $

Simplify the fraction:

$ OR = \frac{288}{108} $

Divide both numerator and denominator by their greatest common divisor (which is 36):

$ OR = \frac{288 \div 36}{108 \div 36} = \frac{8}{3} $

Conclusion

The odds ratio of developing breast cancer among obese women is 8/3.

Was this answer helpful?

Important Questions from Biostatistics

  1. What is the specificity of sputum microscopy in detection of Pulmonary Tuberculosis (PTB) as per the information given below?
     

     PTB Total
    Sputum microscopyPresentAbsent 
    Positive27020290
    Negative30180210
    Total300200500
  2. In a cohort of 500 women attending antenatal clinic, 70 % had ultrasonography (USG). This cohort was followed up at delivery. Of the women who had USG, 70 delivered low birth weight (LBW) babies; whereas of the women, who did not undergo USG, 50 delivered LBW babies. The incidence of LBW babies among women who had USG is:

  3. What is the relative risk of developing pulmonary embolism in users of oral contraceptives as per the information given below?
     

    Women using OCsPulmonary embolismTotal
     YesNo 
    Yes12080200
    No107080
    Total130150280
  4. Which one of the following tests should be applied to compare mean haemoglobin level of two groups of antenatal mothers?

  5. The following table shows the mortality figures among hazardous industry workers :
    Age groupNational death rate per 1000Hazardous industry worker populationObserved deaths
    25-342.030008
    35-443.520009
    45-546.0200013

    What is the Standardized Mortality Ratio (SMR) for the hazardous industry workers (as compared to national popu-lation) ?
Need Expert Advice?

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App