Imagine a light planet is revolving around a star in a circular orbit of radius R with the period of revolution T . If the gravitational force of attraction between the two is proportional to R(-5/2) then
T2 ∝ & R7/2
Planet Orbit Period and Radius Relationship The problem describes a light planet orbiting a star in a circular path with radius R and period T. The gravitational force of attraction between the star and the planet is given to be proportional to R^{-5/2}. Therefore, the correct answer is T 2 ∝ & R 7/2.
Important Questions from Universal law of gravitation
Which of the following is NOT correct ?
Three point masses each of mass m are placed at the three corners of an equilateral triangle of side x. Find the resultant force acting on any one particle at the corner.
Which of the following is NOT correct ?
- Which phenomenon, successfully explained by the universal law of gravitation, relies on the combined and differential gravitational attraction exerted by both the moon and the sun on the earth?
- The law of gravitation helped to prove that:
