If x is subtracted from each of 23, 39, 32 and 56, the numbers so obtained, in this order, are in proportion. What is the mean proportional between (x + 4) and (3x + 1)?
12
The problem states that when a number, let's call it \(x\), is subtracted from each of 23, 39, 32, and 56, the resulting numbers are in proportion. This means that the ratio of the first two numbers is equal to the ratio of the last two numbers.
The numbers obtained after subtracting \(x\) are:
Since these numbers are in proportion, we can write the equation:
\(\frac{23 - x}{39 - x} = \frac{32 - x}{56 - x}\)
To solve for \(x\), we can cross-multiply:
\((23 - x)(56 - x) = (32 - x)(39 - x)\)
Now, we expand both sides of the equation:
\(23 \times 56 - 23x - 56x + x^2 = 32 \times 39 - 32x - 39x + x^2\)
\(1288 - 79x + x^2 = 1248 - 71x + x^2\)
Subtract \(x^2\) from both sides of the equation:
\(1288 - 79x = 1248 - 71x\)
Now, let's rearrange the terms to isolate \(x\). We can add \(79x\) to both sides and subtract \(1248\) from both sides:
\(1288 - 1248 = 79x - 71x\)
\(40 = 8x\)
Divide by 8 to find the value of \(x\):
\(x = \frac{40}{8}\)
\(x = 5\)
So, the value of \(x\) is 5.
The question asks for the mean proportional between \((x + 4)\) and \((3x + 1)\). First, we need to find the values of these two expressions using the calculated value of \(x=5\).
The first term is \((x + 4)\):
\(x + 4 = 5 + 4 = 9\)
The second term is \((3x + 1)\):
\(3x + 1 = 3(5) + 1 = 15 + 1 = 16\)
The numbers are 9 and 16.
The mean proportional between two numbers \(a\) and \(b\) is given by the formula \(\sqrt{ab}\).
In this case, \(a = 9\) and \(b = 16\). The mean proportional is:
\(\sqrt{9 \times 16}\)
Calculate the product inside the square root:
\(\sqrt{144}\)
The square root of 144 is 12.
\(\sqrt{144} = 12\)
Therefore, the mean proportional between \((x + 4)\) and \((3x + 1)\) is 12.
| Concept | Definition | Example |
|---|---|---|
| Proportion | An equality between two ratios. If \(a, b, c, d\) are in proportion, then \(\frac{a}{b} = \frac{c}{d}\). | If 2, 4, 6, 12 are in proportion, then \(\frac{2}{4} = \frac{6}{12}\) (both equal \(\frac{1}{2}\)). |
| Mean Proportional | For two numbers \(a\) and \(b\), the mean proportional \(m\) is a number such that \(a, m, b\) are in geometric progression, meaning \(\frac{a}{m} = \frac{m}{b}\) or \(m^2 = ab\). Thus, \(m = \sqrt{ab}\). | The mean proportional between 4 and 9 is \(\sqrt{4 \times 9} = \sqrt{36} = 6\). |
When four numbers \(a, b, c, d\) are in proportion, written as \(a : b :: c : d\), it means that the ratio of the first term to the second term is equal to the ratio of the third term to the fourth term. Mathematically, this is expressed as \(\frac{a}{b} = \frac{c}{d}\).
In a proportion \(a : b :: c : d\):
A key property of proportion is that the product of the extremes is equal to the product of the means:
\(a \times d = b \times c\)
This property was used in solving the problem when we performed cross-multiplication: \((23-x)(56-x) = (39-x)(32-x)\).
The concept of mean proportional is a special case of proportion. If three numbers \(a, b, c\) are in continued proportion, it means \(a : b :: b : c\), or \(\frac{a}{b} = \frac{b}{c}\). In this case, \(b\) is called the mean proportional between \(a\) and \(c\).
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