$x = a \text{ cosec}A \text{ sin} B,$
$y = b \text{ cosec}A \text{ cos} B,$ and
$z = c \text{ cot} A,$
then, what is the value of $\frac{x^2}{a^2} + \frac{y^2}{b^2} - \frac{z^2}{c^2}$?
We are given the following relationships involving trigonometric functions and variables:
Our goal is to determine the value of the expression $\frac{x^2}{a^2} + \frac{y^2}{b^2} - \frac{z^2}{c^2}$.
Let's first calculate the individual squared terms required for the expression. We rearrange each given equation to isolate the ratio of the variable to its corresponding constant, and then square it.
Now, we substitute these derived squared terms into the target expression:
Expression = $\frac{x^2}{a^2} + \frac{y^2}{b^2} - \frac{z^2}{c^2}$
Substituting the results from the previous step:
Expression = $(\text{cosec}^2A \text{ sin}^2B) + (\text{cosec}^2A \text{ cos}^2B) - (\text{cot}^2A)$
We can simplify this expression by factoring and applying fundamental trigonometric identities.
Notice that $\text{cosec}^2A$ is a common factor in the first two terms:
Expression = $\text{cosec}^2A (\text{sin}^2B + \text{cos}^2B) - \text{cot}^2A$
Using the Pythagorean identity $\text{sin}^2\theta + \text{cos}^2\theta = 1$, we know that $\text{sin}^2B + \text{cos}^2B = 1$. Substituting this:
Expression = $\text{cosec}^2A (1) - \text{cot}^2A$
This simplifies to:
Expression = $\text{cosec}^2A - \text{cot}^2A$
Again, applying a Pythagorean identity, $\text{cosec}^2\theta - \text{cot}^2\theta = 1$. Therefore:
Expression = $1$
The value of the given trigonometric expression $\frac{x^2}{a^2} + \frac{y^2}{b^2} - \frac{z^2}{c^2}$ simplifies to 1.
If $M = \sqrt{\frac{1+\cos A}{1-\cos A}} - \text{cosec} A - \cot A$, and A is an acute angle, then value of M is
Simplify: \( sec^{2} \phi cot^{2 } \phi - \frac{1}{ tan^{2} \phi } +2( \frac{1}{ cosec^{2} \phi }+ \frac{1}{ sec^{2} \phi } )\)