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Question

If two satellites of masses m1 and m2 are revolving around a earth in a circular orbits of radius r1 and r2, then the ratio of their orbital velocities \(\dfrac{v_1}{v_2}\) is

The correct answer is \(\sqrt{\dfrac{r_2}{r_1}}\)

Understanding the Ratio of Orbital Velocities for Satellites

When satellites revolve around the Earth in circular orbits, their speed, known as orbital velocity, depends on the mass of the Earth and the radius of their orbit. The masses of the satellites themselves do not directly affect their orbital velocity in a given orbit.

Formula for Orbital Velocity

The orbital velocity \( v \) of a satellite in a circular orbit around a planet (like Earth) is given by the formula:

\( v = \sqrt{\dfrac{GM}{r}} \)

Where:

  • \( G \) is the universal gravitational constant.
  • \( M \) is the mass of the central body (Earth, in this case).
  • \( r \) is the radius of the circular orbit.

Notice that the mass of the satellite itself (\( m_1 \) or \( m_2 \)) does not appear in this formula. This means the orbital velocity depends only on the mass of the planet and the distance from the center of the planet to the satellite.

Calculating the Ratio of Orbital Velocities

We have two satellites, satellite 1 with mass \( m_1 \) in an orbit of radius \( r_1 \), and satellite 2 with mass \( m_2 \) in an orbit of radius \( r_2 \). Using the orbital velocity formula:

The orbital velocity of satellite 1 is \( v_1 = \sqrt{\dfrac{GM}{r_1}} \).

The orbital velocity of satellite 2 is \( v_2 = \sqrt{\dfrac{GM}{r_2}} \).

To find the ratio of their orbital velocities, \( \dfrac{v_1}{v_2} \), we divide the expression for \( v_1 \) by the expression for \( v_2 \):

\( \dfrac{v_1}{v_2} = \dfrac{\sqrt{\dfrac{GM}{r_1}}}{\sqrt{\dfrac{GM}{r_2}}} \)

We can combine the square roots:

\( \dfrac{v_1}{v_2} = \sqrt{\dfrac{\dfrac{GM}{r_1}}{\dfrac{GM}{r_2}}} \)

Now, simplify the fraction inside the square root. Dividing by a fraction is the same as multiplying by its reciprocal:

\( \dfrac{v_1}{v_2} = \sqrt{\dfrac{GM}{r_1} \times \dfrac{r_2}{GM}} \)

The \( GM \) terms cancel out:

\( \dfrac{v_1}{v_2} = \sqrt{\dfrac{\cancel{GM}}{r_1} \times \dfrac{r_2}{\cancel{GM}}} \)

\( \dfrac{v_1}{v_2} = \sqrt{\dfrac{r_2}{r_1}} \)

Therefore, the ratio of their orbital velocities \( \dfrac{v_1}{v_2} \) is equal to the square root of the inverse ratio of their orbital radii, \( \sqrt{\dfrac{r_2}{r_1}} \). This calculation confirms how the orbital velocity ratio depends only on the radii.

This step-by-step process shows how the ratio of orbital velocities is derived directly from the fundamental formula.

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Important Questions from Gravitation

  1. The known forces of nature can be divided into four classes, viz., gravity, electromagnetism, weak nuclear force and strong nuclear force. With reference to them, which one of the following statements is not correct?

  2. A spacecraft of mass m = 1000 kg has a fully reflecting sail that is oriented perpendicular to the direction of the sun. The sun radiates 10 26 W and has a mass M = 10 30  kg. Ignoring the effect of the planets, for the gravitational pull of the sun to balance the radiation pressure on the sail, the area of the sail will be
  3. The force of attraction between two bodies separated by a distance of d is F. The distance for which the force of attraction between them is 64 F is ________.

  4. A women whose mass is 60 kg on the earth surface is in an spacecraft at an altitude of two times the earth radius. Her mass there is

  5. The gravitational force between two objects of masses m1 and m2 is directly proportional to

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