If two nodes are observed at a frequency of 1800 rpm during whirling of a simply supported long slender rotating shaft, the first critical speed of the shaft in rpm is
200
The question asks us to determine the first critical speed of a simply supported long slender rotating shaft when two nodes are observed at a whirling frequency of 1800 rpm.
Critical speed of a rotating shaft is the speed at which the shaft's rotational frequency matches one of its natural frequencies of transverse vibration. When the shaft rotates at a critical speed, it can experience large amplitudes of vibration, known as whirling, which can lead to excessive stresses and potential failure.
When a shaft vibrates, certain points along its length may remain stationary or have minimal displacement. These points are called nodes. The number of nodes observed corresponds to the mode shape of vibration.
In general, for the \(n\)-th mode of vibration of a simply supported beam or shaft, there are \((n-1)\) nodes between the supports.
For a simply supported long slender rotating shaft, the critical speeds are proportional to the square of the mode number. This relationship can be expressed as:
$$\omega_n = n^2 \omega_1$$
Where:
Given in the problem:
Since 2 nodes are observed during whirling, this corresponds to the third mode of vibration for a simply supported shaft.
Number of nodes \(= n - 1\)
\(2 = n - 1\)
\(n = 2 + 1\)
\(n = 3\)
So, the observed speed of 1800 rpm is the third critical speed (\(\omega_3\)).
We use the relationship:
$$\omega_n = n^2 \omega_1$$
Substitute the known values:
$$\omega_3 = 3^2 \omega_1$$
$$1800 \text{ rpm} = 9 \omega_1$$
$$\omega_1 = \frac{1800}{9}$$
$$\omega_1 = 200 \text{ rpm}$$
Therefore, the first critical speed of the shaft is 200 rpm.
The final answer is 200 rpm.
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