If there was 10 cm of rain over one‐hectare field, what is the total volume (in cubic meters) of rain over the field?
1000
The question asks for the total volume of rain in cubic meters over a one-hectare field, given the depth of rain is 10 cm. To find the volume, we need to multiply the area of the field by the depth of the rain. We must ensure all measurements are in compatible units, specifically meters, to get the final volume in cubic meters.
The given area is 1 hectare. We need to convert hectares to square meters.
The given depth of rain is 10 cm. We need to convert centimeters to meters.
So, the depth of rain in meters is:
$\text{Depth} = 10 \text{ cm} \times 0.01 \frac{\text{m}}{\text{cm}} = 0.1 \text{ m}$
Now we can calculate the total volume of rain using the formula for the volume of a rectangular prism (although the field isn't necessarily a perfect rectangle, the principle of area × height applies):
$\text{Volume} = \text{Area} \times \text{Depth}$
Using the converted values:
$\text{Volume} = 10,000 \text{ m}^2 \times 0.1 \text{ m}$
$\text{Volume} = 1000 \text{ m}^3$
The total volume of rain over the one-hectare field is 1000 cubic meters.
A stone is thrown horizontally from the top of a 20 m high building with a speed of 12 m/s. It hits the ground at a distance R from the building. Taking g = 10 m/s2 and neglecting air resistance will give :
A sphere of volume V is made of a material with lower density than water. While on Earth, it floats on water with its volume f1V (f1 < 1) submerged. On the other hand, on a spaceship accelerating with acceleration a < g (g is the acceleration due to gravity on Earth) in outer space, its submerged volume in water is f2V. Then:
A railway wagon (open at the top) of mass M1 is moving with speed v1 along a straight track. As a result of rain, after some time it gets partially filled with water so that the mass of the wagon becomes M2 and speed becomes v2. Taking the rain to be falling vertically and the water stationery inside the wagon, the relation between the two speeds v1 and v2 is :
Consider the following statements:
1. Distance between the longitudes becomes zero on North Pole and South Pole.
2. Distance between the longitudes is maximum on the Equator.
3. Number of longitudes is more than number of latitudes.
Which of the statements given above is/are correct?
One block of 2⋅0 kg mass is placed on top of another block of 3⋅0 kg mass. The coefficient of static friction between the two blocks is 0⋅2. The bottom block is pulled with a horizontal force F such that both the blocks move together without slipping. Taking acceleration due to gravity as 10 m/s2, the maximum value of the frictional force is :