If the velocity of a body is doubled its kinetic energy _______.
become 4 times
Kinetic energy is the energy a body possesses due to its motion. The amount of kinetic energy depends on the mass of the body and its velocity. The relationship between kinetic energy and velocity is described by a specific formula.
The kinetic energy (\(KE\)) of a body with mass \(m\) and velocity \(v\) is given by the formula:
\(KE = \frac{1}{2}mv^2\)
This formula shows that kinetic energy is directly proportional to the mass (\(m\)) and the square of the velocity (\(v^2\)). This means if either the mass or velocity changes, the kinetic energy will also change.
Let's consider a body with a certain mass \(m\) and an initial velocity \(v_1\). Its initial kinetic energy, \(KE_1\), is:
\(KE_1 = \frac{1}{2}mv_1^2\)
The question states that the velocity of the body is doubled. So, the new velocity, \(v_2\), is \(v_2 = 2v_1\). We want to find the new kinetic energy, \(KE_2\), with this new velocity:
\(KE_2 = \frac{1}{2}mv_2^2\)
Now, substitute the new velocity \(v_2 = 2v_1\) into the formula for \(KE_2\):
\(KE_2 = \frac{1}{2}m(2v_1)^2\)
When we square the term \(2v_1\), we get \((2v_1)^2 = 2^2 \times v_1^2 = 4v_1^2\). So, the equation becomes:
\(KE_2 = \frac{1}{2}m(4v_1^2)\)
We can rearrange the terms:
\(KE_2 = 4 \times (\frac{1}{2}mv_1^2)\)
Notice that the term inside the parentheses, \((\frac{1}{2}mv_1^2)\), is the initial kinetic energy, \(KE_1\). Therefore, we can write:
\(KE_2 = 4 \times KE_1\)
This calculation shows that when the velocity of the body is doubled, its kinetic energy becomes four times its original value.
| Quantity | Initial State | Final State (Velocity Doubled) |
|---|---|---|
| Mass | \(m\) | \(m\) |
| Velocity | \(v\) | \(2v\) |
| Kinetic Energy (KE = \(\frac{1}{2}mv^2\)) | \(KE_1 = \frac{1}{2}mv^2\) | \(KE_2 = \frac{1}{2}m(2v)^2 = \frac{1}{2}m(4v^2) = 4 \times (\frac{1}{2}mv^2) = 4KE_1\) |
Based on the formula \(KE = \frac{1}{2}mv^2\), the kinetic energy is proportional to the square of the velocity. If the velocity is multiplied by a factor (let's say \(n\)), the kinetic energy will be multiplied by \(n^2\). In this question, the velocity is multiplied by 2, so the kinetic energy is multiplied by \(2^2 = 4\).
Therefore, if the velocity of a body is doubled, its kinetic energy becomes 4 times the original kinetic energy.
| Concept | Description | Formula |
|---|---|---|
| Kinetic Energy | Energy possessed by a body due to its motion. | \(KE = \frac{1}{2}mv^2\) |
| Mass (m) | A measure of the amount of matter in a body. (Unit: kg) | Directly proportional to KE |
| Velocity (v) | The rate of change of position of a body with respect to time in a given direction. (Unit: m/s) | KE is proportional to the square of velocity (\(v^2\)) |
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