If the temperature increases by 10°C, the P-N junction barrier voltage
A P-N junction is a fundamental building block of many semiconductor devices. It is formed when a p-type semiconductor and an n-type semiconductor are brought into intimate contact. At the interface, a region called the depletion region is formed. This region is depleted of mobile charge carriers (electrons and holes) and contains immobile charged impurity ions. The electric field created by these immobile charges establishes a potential difference across the depletion region, which is known as the barrier voltage or built-in potential (\(V_0\)). This barrier voltage prevents the free flow of majority carriers across the junction in equilibrium.
The barrier voltage of a P-N junction is significantly influenced by temperature. As the temperature of the semiconductor material changes, its electrical properties, including the barrier voltage, are affected. Specifically, for most semiconductor diodes (like silicon and germanium), an increase in temperature leads to a decrease in the barrier voltage. Conversely, a decrease in temperature causes the barrier voltage to increase.
This behavior can be explained by considering the following points:
The rate at which the P-N junction barrier voltage changes with temperature is commonly referred to as its temperature coefficient. For silicon diodes, the barrier voltage typically decreases by approximately 2 mV to 2.5 mV for every 1°C rise in temperature. However, based on the options provided for a 10°C temperature increase, we need to find the change that aligns with the given values.
The question states that the temperature increases by 10°C. According to the correct answer, the P-N junction barrier voltage decreases by 0.002 V.
Let's verify how this change occurs:
\[ \text{Total Change in Barrier Voltage} = \text{Rate of Change} \times \text{Change in Temperature} \]
If the barrier voltage decreases by 0.002 V for a 10°C increase, the effective rate of change (temperature coefficient) for this specific scenario can be calculated:
\[ \text{Rate of Change} = \frac{\text{Total Change in Barrier Voltage}}{\text{Change in Temperature}} \]
\[ \text{Rate of Change} = \frac{0.002 \text{ V}}{10 \text{ °C}} \]
\[ \text{Rate of Change} = 0.0002 \text{ V/°C} \]
\[ \text{Rate of Change} = 0.2 \text{ mV/°C} \]
Thus, for a 10°C increase in temperature, the P-N junction barrier voltage decreases by 0.002 V. This indicates a very small temperature coefficient of 0.2 mV/°C for the specific conditions presented in the question.
Understanding the sensitivity of P-N junction barrier voltage to temperature is vital for designing and analyzing semiconductor circuits. Here are the key points to remember:
Diode junction breakdowns above 5 V are caused by:
The leakage current in a pn junction is of the order of:
For a PN junction, we have
A. Width of depletion layer
B. Junction barrier voltage
C. Reverse leakage current
Which of the above parameters will decrease when the temperature of the junction rises?
The depletion region consists of:
In the P-N junction, the barrier voltage