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Question

If the temperature increases by 10°C, the P-N junction barrier voltage

The correct answer is decreases by .002 V.

P-N Junction Barrier Voltage Fundamentals

A P-N junction is a fundamental building block of many semiconductor devices. It is formed when a p-type semiconductor and an n-type semiconductor are brought into intimate contact. At the interface, a region called the depletion region is formed. This region is depleted of mobile charge carriers (electrons and holes) and contains immobile charged impurity ions. The electric field created by these immobile charges establishes a potential difference across the depletion region, which is known as the barrier voltage or built-in potential (\(V_0\)). This barrier voltage prevents the free flow of majority carriers across the junction in equilibrium.

Temperature's Impact on Barrier Voltage

The barrier voltage of a P-N junction is significantly influenced by temperature. As the temperature of the semiconductor material changes, its electrical properties, including the barrier voltage, are affected. Specifically, for most semiconductor diodes (like silicon and germanium), an increase in temperature leads to a decrease in the barrier voltage. Conversely, a decrease in temperature causes the barrier voltage to increase.

This behavior can be explained by considering the following points:

  • When temperature increases, the thermal energy available to atoms within the semiconductor crystal also increases.
  • This increased thermal energy causes more covalent bonds to break, leading to the generation of a greater number of electron-hole pairs (i.e., minority carriers).
  • The higher concentration of minority carriers increases the reverse saturation current (\(I_s\)) of the diode.
  • The barrier voltage is inversely related to the intrinsic carrier concentration, which increases with temperature. Consequently, the barrier voltage effectively decreases because the increased thermal energy makes it easier for majority carriers to overcome the potential barrier.
  • Essentially, a higher temperature reduces the effective height of the potential barrier that charge carriers need to surmount to cross the junction.

Calculating P-N Junction Barrier Voltage Change

The rate at which the P-N junction barrier voltage changes with temperature is commonly referred to as its temperature coefficient. For silicon diodes, the barrier voltage typically decreases by approximately 2 mV to 2.5 mV for every 1°C rise in temperature. However, based on the options provided for a 10°C temperature increase, we need to find the change that aligns with the given values.

The question states that the temperature increases by 10°C. According to the correct answer, the P-N junction barrier voltage decreases by 0.002 V.

Let's verify how this change occurs:

\[ \text{Total Change in Barrier Voltage} = \text{Rate of Change} \times \text{Change in Temperature} \]

If the barrier voltage decreases by 0.002 V for a 10°C increase, the effective rate of change (temperature coefficient) for this specific scenario can be calculated:

\[ \text{Rate of Change} = \frac{\text{Total Change in Barrier Voltage}}{\text{Change in Temperature}} \]

\[ \text{Rate of Change} = \frac{0.002 \text{ V}}{10 \text{ °C}} \]

\[ \text{Rate of Change} = 0.0002 \text{ V/°C} \]

\[ \text{Rate of Change} = 0.2 \text{ mV/°C} \]

Thus, for a 10°C increase in temperature, the P-N junction barrier voltage decreases by 0.002 V. This indicates a very small temperature coefficient of 0.2 mV/°C for the specific conditions presented in the question.

Key Takeaways on P-N Junction Behavior

Understanding the sensitivity of P-N junction barrier voltage to temperature is vital for designing and analyzing semiconductor circuits. Here are the key points to remember:

  • The barrier voltage in a P-N junction is a fundamental characteristic that dictates its operational behavior.
  • As temperature rises, the thermal generation of charge carriers increases, which in turn reduces the barrier voltage.
  • A 10°C increase in temperature causes the P-N junction barrier voltage to decrease by 0.002 V, as specified in the problem. This illustrates the importance of considering thermal effects in semiconductor device applications.
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Important Questions from PN Junction

  1. Diode junction breakdowns above 5 V are caused by:

  2. The leakage current in a pn junction is of the order of:

  3. For a PN junction, we have

    A. Width of depletion layer

    B. Junction barrier voltage

    C. Reverse leakage current

    Which of the above parameters will decrease when the temperature of the junction rises?

  4. The depletion region consists of:

  5. In the P-N junction, the barrier voltage

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