If the sum of the first 14 terms of an AP is 1050 and its first term is 10, then its 20th term is:
200
The question asks us to find the 20th term of an Arithmetic Progression (AP). We are given the sum of the first 14 terms and the first term of the AP.
An Arithmetic Progression is a sequence of numbers such that the difference between the consecutive terms is constant. This constant difference is called the common difference, denoted by 'd'.
We are given the following information:
We need to find the 20th term (\(a_{20}\)). To find \(a_{20}\), we first need to determine the common difference (d) of the AP.
We can use the formula for the sum of the first n terms of an AP:
\(S_n = \frac{n}{2}[2a + (n-1)d]\)
Substitute the given values into the formula with n=14:
\(S_{14} = \frac{14}{2}[2a + (14-1)d]\)
\(1050 = 7[2(10) + 13d]\)
Now, simplify and solve for d:
\(1050 = 7[20 + 13d]\)
Divide both sides by 7:
\(\frac{1050}{7} = 20 + 13d\)
\(150 = 20 + 13d\)
Subtract 20 from both sides:
\(150 - 20 = 13d\)
\(130 = 13d\)
Divide both sides by 13:
\(d = \frac{130}{13}\)
\(d = 10\)
The common difference of the AP is 10.
Now that we have the first term (a=10) and the common difference (d=10), we can find the 20th term using the formula for the n-th term:
\(a_n = a + (n-1)d\)
Substitute a=10, d=10, and n=20 into the formula:
\(a_{20} = 10 + (20-1)10\)
\(a_{20} = 10 + (19)10\)
\(a_{20} = 10 + 190\)
\(a_{20} = 200\)
The 20th term of the Arithmetic Progression is 200.
Given:
Calculated:
| Information | Value |
|---|---|
| First Term (a) | 10 |
| Sum of first 14 terms (\(S_{14}\)) | 1050 |
| Number of terms (n) | 14 (for sum calculation) |
| Calculated Common Difference (d) | 10 |
| Term to find (n) | 20 |
| Resulting 20th Term (\(a_{20}\)) | 200 |
| Concept | Formula | Description |
|---|---|---|
| n-th term (\(a_n\)) | \(a_n = a + (n-1)d\) | Finds the value of the term at the n-th position. |
| Sum of first n terms (\(S_n\)) | \(S_n = \frac{n}{2}[2a + (n-1)d]\) | Finds the sum of the first n terms using 'a' and 'd'. |
| Sum of first n terms (\(S_n\)) | \(S_n = \frac{n}{2}(a + a_n)\) | Finds the sum of the first n terms using 'a' and the n-th term. |
| Common Difference (d) | \(d = a_n - a_{n-1}\) | The constant difference between consecutive terms. |
Arithmetic Progressions are fundamental sequences in mathematics. They appear in various applications, from simple counting patterns to more complex financial calculations.
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