If the scale height for pressure in atmosphere is assumed to be 7 km, what will be the pressure at a height of 21 km above the ground surface?
∼ 5 × 103 Pa
The atmospheric pressure decreases with altitude due to the decreasing weight of the air column above. In a simplified model, assuming the atmosphere is isothermal (constant temperature) and composed of an ideal gas, the pressure ($P$) at a height ($h$) above the ground is related to the pressure at the ground level ($P_0$) by the formula:
\( P(h) = P_0 e^{-h/H} \)
where:
In this specific problem, we are given:
We need to find the pressure at a height of 21 km, \(P(21 \text{ km})\). We need to assume a value for the pressure at ground level (\(P_0\)). A standard value for atmospheric pressure at sea level is approximately \(10^5\) Pa (or 1 atm). Let's use this value for \(P_0\).
\(P_0 \approx 1 \times 10^5 \text{ Pa}\)
Now we can substitute the given values into the formula:
\( P(21 \text{ km}) = P_0 e^{-21 \text{ km} / 7 \text{ km}} \)
\( P(21 \text{ km}) = P_0 e^{-3} \)
Next, we need to calculate the value of \(e^{-3}\).
\( e^{-3} = \frac{1}{e^3} \)
Using the approximate value \(e \approx 2.71828\):
\( e^3 \approx (2.71828)^3 \approx 20.0855 \)
\( e^{-3} \approx \frac{1}{20.0855} \approx 0.049787 \)
Now multiply this by \(P_0 = 1 \times 10^5 \text{ Pa}\):
\( P(21 \text{ km}) \approx (1 \times 10^5 \text{ Pa}) \times 0.049787 \)
\( P(21 \text{ km}) \approx 4978.7 \text{ Pa} \)
Rounding this value and expressing it in scientific notation gives:
\( P(21 \text{ km}) \approx 4.98 \times 10^3 \text{ Pa} \)
Looking at the given options:
Our calculated value of approximately \(4.98 \times 10^3 \text{ Pa}\) is closest to Option 1, which is \(\sim 5 \times 10^3 \text{ Pa}\). The result is very close to \(5000 \text{ Pa}\).
| Concept | Description | Formula (Simplified) |
|---|---|---|
| Atmospheric Pressure | The force exerted by the weight of the air above a unit area. Decreases with increasing altitude. | \(P\) |
| Scale Height (\(H\)) | A characteristic height over which atmospheric pressure (or density) decreases by a factor of \(e\). It depends on temperature, molecular weight of air, and gravitational acceleration. | \(H = \frac{kT}{mg}\) (for a single gas, isothermal) |
| Pressure-Altitude Relation | Describes how pressure changes with height, assuming an isothermal atmosphere and constant gravity. | \( P(h) = P_0 e^{-h/H} \) |
The concept of scale height is a useful approximation for understanding the general behavior of atmospheric pressure with altitude. Here are some important points:
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