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Question

If the drainable porosity of a command area is $5\%$ and the design rate of drop of the water table is $0.25 \text{ m day}^{-1}$, the drainage coefficient of the command area in $\text{mm day}^{-1}$ will be

The correct answer is
$12.5$

Calculate Drainage Coefficient

The drainage coefficient represents the depth of water to be removed by a drainage system in a given period. It can be calculated using the drainable porosity and the rate at which the water table drops.

Formula for Drainage Coefficient

The drainage coefficient ($D$) is calculated using the following formula:

$ D = n_e \times R $

Where:

  • $D$ = Drainage coefficient (in meters per day, initially)
  • $n_e$ = Drainable porosity (dimensionless)
  • $R$ = Rate of drop of the water table (in meters per day)

Given Data

  • Drainable porosity ($n_e$): $5\% = 0.05$
  • Rate of drop of water table ($R$): $0.25 \text{ m day}^{-1}$

Calculation Steps

  1. Calculate Drainage Coefficient in Meters: Substitute the given values into the formula.

    $ D = 0.05 \times 0.25 \text{ m day}^{-1} $

    $ D = 0.0125 \text{ m day}^{-1} $

  2. Convert to Millimeters: Since the answer is required in $\text{mm day}^{-1}$, convert meters to millimeters ($1 \text{ m} = 1000 \text{ mm}$).

    $ D = 0.0125 \times 1000 \text{ mm day}^{-1} $

    $ D = 12.5 \text{ mm day}^{-1} $

Therefore, the drainage coefficient of the command area is $12.5 \text{ mm day}^{-1}$.

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Important Questions from Drainage Coefficient

  1. A tile drainage system having a drainage coefficient of $25\text{ mm}$ drains an area of $0.2\text{ km}^2$. The average discharge from the system (in $\text{m}^3\text{.s}^{-1}$) is ________. (Rounded off to three decimal places)
  2. The drainage coefficient of a watershed of $720$ ha area is $1.2$ cm. The design discharge of the drain in m$^3$ s$^{-1}$ is ________
  3. The excess water from a watershed of area 16.95 km$^2$ is drained out through a channel at an average rate of 2.8 m$^3$.s$^{-1}$. Drainage coefficient of the watershed, in cm, is _________. (Rounded off to 2 decimal places)
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