If the diameter of a solid steel bar is to be designed for torque T, then the permissible shear stress is considered as:
When designing engineering components, such as a solid steel bar intended to withstand a specific torque T, it is essential to determine the maximum allowable stress the material can safely endure. This is known as the permissible stress or allowable stress. This calculated value ensures the component functions reliably without failure or excessive deformation under operational loads.
The concept of permissible stress is a cornerstone in mechanical design. It is derived by considering the material's inherent strength properties and applying a factor of safety. The choice of which material strength property to use (e.g., ultimate stress or yield stress) largely depends on whether the material is ductile or brittle.
The factor of safety is a critical design parameter that provides a margin against failure. It is typically defined as the ratio of a material's strength to the actual or expected maximum stress applied during service. For design purposes, it's used to calculate the permissible stress:
\[ \text{Permissible Stress} = \frac{\text{Material Strength}}{\text{Factor of Safety}} \]
A higher factor of safety indicates a more conservative and typically safer design, although it may lead to larger or heavier components.
For ductile materials such as a solid steel bar, especially when subjected to shear stress caused by torque T, the design calculation for permissible stress is based on the material's yield stress. This is because ductile materials show significant plastic deformation beyond the yield point, which for most engineering applications is considered a failure.
When dealing with shear stress, it's important to understand the relationship between the material's tensile yield stress (\(\sigma_y\)) and its shear yield stress (\(\tau_y\)). According to widely accepted theories of failure for ductile materials (like the Tresca or Von Mises criterion), the shear yield stress is often taken as approximately half of the tensile yield stress:
\[ \tau_y \approx \frac{\sigma_y}{2} \]
Therefore, to determine the permissible shear stress (\(\tau_{perm}\)) for a solid steel bar designed for torque T, we apply the factor of safety to the shear yield stress:
\[ \tau_{perm} = \frac{\text{Shear Yield Stress}}{\text{Factor of Safety}} \]
By substituting the relationship between shear yield stress and tensile yield stress into the formula, we get:
\[ \tau_{perm} = \frac{\left(\frac{\text{Yield Stress}}{2}\right)}{\text{Factor of Safety}} \]
This simplifies to the formula for permissible shear stress:
\[ \tau_{perm} = \frac{\text{Yield Stress}}{(2 \times \text{Factor of safety})} \]
This formula ensures that the design is safe, accounting for both the material's yielding behavior under shear and the necessary safety margin.
Let's evaluate each given option against the principles of mechanical design for a solid steel bar under torque T:
Considering the material (steel, which is ductile) and the type of stress (shear stress due to torque), the most appropriate formula for permissible shear stress for a solid steel bar designed for torque T is the one that uses yield stress and includes the factor of '2' in the denominator to account for the shear strength relationship.
A tubular shaft, having an inner diameter of 30 mm and an outer diameter of 40 mm, is to be used to transmit 80 kW of power. The speed of rotation of the shaft so that the shear stress will not exceed 50 MPa is
The magnitude of shear stress induced in a shaft due to applied torque varies from:
What is the maximum torque transmitted by a hollow shaft of external radius ‘R’, internal radius ‘r’ and maximum allowable shear stress τ?