To determine if a number is divisible by 11, we use a specific rule. This rule involves the alternating sum of the digits. We sum the digits in the odd positions (starting from the rightmost digit as position 1) and subtract the sum of the digits in the even positions. If the result is 0 or any multiple of 11 (like 11, 22, -11, -22, etc.), the original number is divisible by 11.
The given 6-digit number is N01M22.
Let's identify the digits and their positions from right to left:
Now, let's calculate the sum of digits at odd positions and even positions:
According to the divisibility rule for 11, the difference between these sums must be a multiple of 11.
Difference = (Sum of odd positioned digits) - (Sum of even positioned digits)
Difference = $(M + 2) - (N + 3)$
Difference = $M + 2 - N - 3$
Difference = $M - N - 1$
So, for N01M22 to be divisible by 11, the expression $M - N - 1$ must be a multiple of 11.
We can write this as:
$ M - N - 1 = 11k $ where $k$ is an integer ($k \in \{..., -2, -1, 0, 1, 2, ...\}$).Rearranging the equation, we get:
$ M - N = 11k + 1 $We know that M and N are digits. Since N is the first digit of a 6-digit number, N cannot be 0. Therefore:
Let's find the possible range for the difference $M - N$:
So, the difference $M - N$ must be within the range $[-9, 8]$.
Now let's test values of $k$ in the equation $M - N = 11k + 1$:
Therefore, the only possible relation between M and N that satisfies the divisibility rule for 11 is $M - N = 1$.
Let's check which option matches our derived relation $M - N = 1$.
| Option Number | Relation Provided | Matches Derived Rule ($M - N = 1$)? |
| 1 | $M - N = 1$ | Yes |
| 2 | $M + N = -1$ | No (This represents a different relationship) |
| 3 | $M - N = 5$ | No (This is a possible difference, but not the one required by the divisibility rule) |
| 4 | $M = N$ | No (This implies $M - N = 0$, which does not match) |
| 5 | (Not specified) | N/A |
Based on the divisibility rule for 11 and the constraints on the digits M and N, the only possible relation is $M - N = 1$. This matches Option 1.
Find the least value of x for which 57x716 is divisible by 9.
Which of the following numbers is NOT divisible by 11?
If 321y72 is a multiple of 6, where y is a digit, what is the least value of y?
From the given numbers A, B, C and D, which number is NOT divisible by 11?
A = 712712
B = 177210
C = 64614
D = 756148
Which of the following numbers is divisible by 7 ?