If P and Q are two sets, then (P - Q) ∪ (Q - P) ∪ (P ∩ Q) will be
P ∪ Q
The question asks us to simplify the expression $$(P - Q) \cup (Q - P) \cup (P \cap Q)$$ where P and Q are two sets. This involves combining several fundamental set operations: set difference, intersection, and union. Let's break down each part of the expression based on basic set theory principles.
Consider two sets, P and Q. We can think of the elements in these sets being divided into different regions:
The expression asks for the union of sets of these three resulting sets: $$(P - Q) \cup (Q - P) \cup (P \cap Q)$$ The union operation combines all elements from the sets being united. So, we are taking all elements that are either:
Let's visualize this using the idea of a Venn diagram for two sets P and Q. The three regions we are considering are mutually exclusive (they have no elements in common):
When we take the union of sets of these three regions, we are including every element that falls into any one of these areas. Together, these three regions cover every single element that is in set P, or in set Q, or in both sets P and Q.
By definition, the union of sets P and Q, denoted as $P \cup Q$, is the set of all elements that are in P, or in Q, or in both P and Q. This is exactly what the union of the three regions $(P - Q)$, $(Q - P)$, and $(P \cap Q)$ represents.
Therefore, the expression $$(P - Q) \cup (Q - P) \cup (P \cap Q)$$ simplifies to $P \cup Q$. This is a fundamental result in set theory that shows how the parts of a Venn diagram for two sets relate to the overall union.
Understanding these fundamental set operations is crucial for solving problems in set theory.
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