This problem requires calculating the rate of stationery usage to determine how long it takes for a different number of students to use a specific amount of stationery.
The relationship between total pages ($S$), number of students ($N$), number of days ($D$), and the rate of usage ($R$) per student per day is:
$S = R \times N \times D$
We are given that $m$ students require $m$ pages in $m$ days.
Substitute these values to find the rate $R$:
$m = R \times m \times m$
$m = R \times m^2$
Solve for $R$:
$R = \frac{m}{m^2} = \frac{1}{m}$ pages per student per day.
We need to find the number of days ($D$) for 100 students to use 100 pages, using the rate $R = \frac{1}{m}$.
Using the formula $S = R \times N \times D$:
$100 = \frac{1}{m} \times 100 \times D$
$100 = \frac{100}{m} \times D$
Rearrange the equation to solve for $D$:
Multiply both sides by $m$:
$100 \times m = 100 \times D$
Divide both sides by 100:
$D = \frac{100 \times m}{100}$
$D = m$
100 students will require 100 pages of stationery in $m$ days. This matches Option 4.