If logx y = 100 and log2 x = 10, then the value of y is:
21000
This problem involves solving a system of two logarithmic equations to find the value of an unknown variable, y. We are given:
logx y = 100log2 x = 10Our goal is to determine the value of y using the information provided. We can solve this by converting the logarithmic equations into their equivalent exponential forms and using substitution.
First, let's use the second equation, log2 x = 10. The definition of a logarithm states that if logb a = c, then it is equivalent to the exponential form bc = a.
Applying this definition to log2 x = 10:
The base (b) is 2.
The result (c) is 10.
The argument (a) is x.
Converting to exponential form, we get: $$x = 2^{10}$$
Now we know the value of x. Let's substitute this value into the first equation, logx y = 100.
Substitute $x = 2^{10}$: $$log_{2^{10}} y = 100$$
Again, we convert this logarithmic equation into its exponential form. Here: The base (b) is $2^{10}$. The result (c) is 100. The argument (a) is y.
Converting to exponential form, we get: $$y = (2^{10})^{100}$$
To find the final value of y, we need to simplify the expression $ (2^{10})^{100} $. We use the rule of exponents which states that $(a^m)^n = a^{m \times n}$.
Applying this rule: $$y = 2^{10 \times 100}$$ $$y = 2^{1000}$$
So, the value of y is $2^{1000}$.
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