If f(x) = x2 for each x ϵ (-∞,∞), then \(\frac{{f(f\left( {f\left( x \right))} \right)}}{{f\left( x \right)}}\) is equal to ___
(f(x))3
This problem asks us to evaluate a complex function expression involving nested functions. We are given the function \(f(x) = x^2\) and need to find the value of \(\frac{{f(f\left( {f\left( x \right))} \right)}}{{f\left( x \right)}}\).
The core of this problem lies in understanding the given function:
Let's evaluate the nested function \(f(f(f(x)))\) step-by-step from the innermost part outwards.
The innermost function is simply \(f(x)\).
Now we evaluate \(f\) of the result from the first level. Replace the input \(x\) in \(f(x)\) with \(f(x)\) itself.
Finally, we evaluate \(f\) of the result from the second level. Replace the input \(x\) in \(f(x)\) with \(f(f(x))\), which we found to be \(x^4\).
Now that we have both the numerator \(f(f(f(x))) = x^8\) and the denominator \(f(x) = x^2\), we can substitute these into the given expression:
\(\frac{{f(f\left( {f\left( x \right))} \right)}}{{f\left( x \right)}} = \frac{x^8}{x^2}\)
Using the exponent rule for division \(\frac{a^m}{a^n} = a^{m-n}\):
\(\frac{x^8}{x^2} = x^{8-2} = x^6\)
So, the expression simplifies to \(x^6\).
The options are given in terms of \(f(x)\), so we need to express \(x^6\) using \(f(x)\). Recall that \(f(x) = x^2\).
We can rewrite \(x^6\) as:
\(x^6 = (x^2)^3\)
Since \(f(x) = x^2\), we can substitute \(f(x)\) for \(x^2\):
\((x^2)^3 = (f(x))^3\)
Therefore, \(\frac{{f(f\left( {f\left( x \right))} \right)}}{{f\left( x \right)}} = (f(x))^3\).
| Step | Calculation | Result |
|---|---|---|
| 1. Initial Function | Given \(f(x) = x^2\) | \(x^2\) |
| 2. First Nesting | \(f(f(x)) = f(x^2)\) | \((x^2)^2 = x^4\) |
| 3. Second Nesting | \(f(f(f(x))) = f(x^4)\) | \((x^4)^2 = x^8\) |
| 4. Final Division | \(\frac{f(f(f(x)))}{f(x)} = \frac{x^8}{x^2}\) | \(x^{8-2} = x^6\) |
| 5. Express in terms of \(f(x)\) | \(x^6 = (x^2)^3\) | \((f(x))^3\) |
The final result matches option 3.
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