If E = 10; J = 20; O = 30; and T = 40, what will be P + E + S + T?
120
The problem presents a pattern where certain letters are assigned numerical values. We need to identify this pattern and then apply it to find the sum of the values of P, E, S, and T.
Let's carefully examine the given information to uncover the underlying rule:
We can observe that these letters (E, J, O, T) correspond to specific positions in the English alphabet:
Comparing the alphabetical position with the assigned value, we can see a clear relationship:
Therefore, the pattern is: Value = Alphabetical Position × 2.
Now, let's use this identified pattern to find the values of P, E, S, and T.
| Letter | Alphabetical Position | Calculated Value (Position × 2) |
|---|---|---|
| P | 16 | 16 × 2 = 32 |
| E | 5 | 5 × 2 = 10 |
| S | 19 | 19 × 2 = 38 |
| T | 20 | 20 × 2 = 40 |
Finally, we need to calculate the sum of these determined values:
\( P + E + S + T = 32 + 10 + 38 + 40 \)
Let's add them step-by-step:
The total sum is 120.
Based on the alphabetical pattern where each letter's value is twice its position in the alphabet, the sum P + E + S + T is 120.
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