Direction: Questions are based on the following: There are five persons A, B, C, D, E standing on six steps numbered 1, 2, 3, 4, 5 and 6 from the bottom. At most one person is standing on each step. The step number, on which A is standing, is two less than that of C. Step number on which B is standing is one more than that of D.
If D is standing on step 1, on which step A could be standing?
3 or 4 only
This problem involves determining the possible position of person A on a set of steps, given certain conditions about the relative positions of different people.
We have five people (A, B, C, D, E) standing on six steps numbered 1 to 6 from the bottom. The rules governing their positions are:
Step(A) = Step(C) - 2
Or equivalently,
Step(C) = Step(A) + 2
Step(B) = Step(D) + 1
We are told that person D is standing on step 1.
Using the second condition, Step(B) = Step(D) + 1:
So, steps 1 and 2 are occupied by D and B, respectively.
The steps available for the remaining people (A, C, and E) are 3, 4, 5, and 6.
Now, let's use the first condition, Step(C) = Step(A) + 2, to find the possible positions for A among the available steps {3, 4, 5, 6}. We need to find pairs of steps $(A, C)$ from this set where C's step number is exactly 2 greater than A's step number.
Therefore, the only possible steps on which A could be standing are step 3 or step 4.
Based on our analysis, A can be on step 3 or step 4. Comparing this with the given options:
The correct option states that A could be standing on step 3 or step 4.
If T joined P, Q, R and S, and T was on the third step, and Q was on a higher step than T, which step must be vacant?
If there are two steps in between the steps on which A and D are standing and C is standing on Step 6, A must be standing on which of the following steps?