If a person weighs 66 N on the Earth, how much is his weight on the moon?
11 N
This question asks us to find a person's weight on the Moon given their weight on the Earth. To solve this, we need to understand what weight is and how gravity affects it.
Understanding Weight and Gravity
Gravity on the Moon compared to Earth
The acceleration due to gravity on the surface of the Moon is approximately one-sixth (\(1/6\)) of the acceleration due to gravity on the surface of the Earth. Let's denote the acceleration due to gravity on Earth as \(g_e\) and on the Moon as \(g_m\). Then, \(g_m \approx \frac{1}{6} g_e\).
Calculating Weight on the Moon
Let \(m\) be the mass of the person. The person's weight on Earth (\(W_e\)) is given by:
\( W_e = m \times g_e \)
The person's weight on the Moon (\(W_m\)) is given by:
\( W_m = m \times g_m \)
Since \(g_m \approx \frac{1}{6} g_e\), we can substitute this into the equation for \(W_m\):
\( W_m = m \times \left(\frac{1}{6} g_e\right) \)
\( W_m = \frac{1}{6} \times (m \times g_e) \)
Notice that \(m \times g_e\) is the weight on Earth, \(W_e\). So, we can write:
\( W_m = \frac{1}{6} W_e \)
The question states that the person's weight on Earth is 66 N.
Substituting the value of \(W_e\) into the equation:
\( W_m = \frac{1}{6} \times 66 \, \text{N} \)
Now, we calculate the value:
\( W_m = \frac{66}{6} \, \text{N} \)
\( W_m = 11 \, \text{N} \)
So, the person's weight on the Moon is 11 N.
Comparing with Options
Let's look at the given options:
Our calculated weight on the Moon is 11 N, which matches one of the options.
Conclusion
Based on the calculation using the relationship between gravitational acceleration on the Earth and the Moon, a person weighing 66 N on Earth would weigh 11 N on the Moon.
| Concept | Definition | Unit | Varies? |
|---|---|---|---|
| Mass | Amount of matter in an object | kilograms (kg) | No (constant everywhere) |
| Weight | Force of gravity on an object's mass | Newtons (N) | Yes (depends on gravity) |
| Acceleration due to gravity (g) | Acceleration experienced by an object due to gravity | meters per second squared (m/s²) | Yes (differs on different planets/moons) |
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