This problem involves calculating the number of students required based on the amount of work (charts prepared) and the time taken. We can use the principle of combined variation or proportionality.
Let $S$ be the number of students, $C$ be the number of charts, and $T$ be the time in hours. The number of students needed is directly proportional to the number of charts and inversely proportional to the time taken.
This can be expressed as: $ \frac{S \times T}{C} = k $ where $k$ is a constant representing the work rate per student.
Using the initial condition:
Using the condition to find:
We set up the proportion:
$ \frac{S_1 \times T_1}{C_1} = \frac{S_2 \times T_2}{C_2} $Substitute the known values:
$ \frac{9 \times 3}{117} = \frac{S_2 \times 1}{208} $Simplify the left side:
$ \frac{27}{117} = \frac{S_2}{208} $Reduce the fraction $\frac{27}{117}$ by dividing both numerator and denominator by their greatest common divisor, which is 9:
$ \frac{3}{13} = \frac{S_2}{208} $Now, solve for $S_2$:
$ S_2 = \frac{3 \times 208}{13} $Calculate the value:
$ S_2 = 3 \times 16 $ $ S_2 = 48 $Therefore, 48 students are needed.
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