If 5 times A's age is added to B's age, the sum is 95 years. If 2.2 times B's age is added to A's age, the sum is 63 years. What is B's age (in years)?
This problem involves finding the ages of two individuals, A and B, based on relationships given between their ages. We need to set up and solve a system of linear equations to find B's age.
Let's denote the age of A as $A$ and the age of B as $B$. We can translate the information given in the question into two mathematical equations:
We have a system of two linear equations with two variables:
We can use the substitution method to solve this system. First, let's isolate $B$ in Equation 1:
From Equation 1: $B = 95 - 5A$
Now, substitute this expression for $B$ into Equation 2:
$A + 2.2(95 - 5A) = 63$
Distribute the 2.2:
$A + (2.2 \times 95) - (2.2 \times 5A) = 63$
$A + 209 - 11A = 63$
Combine the terms with $A$:
$209 - 10A = 63$
Now, we need to solve for $A$. Subtract 209 from both sides:
$-10A = 63 - 209$
$-10A = -146$
Divide by -10:
$A = \frac{-146}{-10}$
$A = 14.6$
So, A's age is 14.6 years. Now we can find B's age using the expression we found earlier ($B = 95 - 5A$):
$B = 95 - 5(14.6)$
$B = 95 - 73$
$B = 22$
Let's check if these ages satisfy the original conditions:
Both conditions are satisfied.
Based on the calculations, B's age is 22 years.
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