If 3 ≤ x ≤ 10 and 5 ≤ y ≤ 15, then minimum value of \(\left(\frac{x}{y}\right)\) is
To determine the minimum value of the expression \(\left(\frac{x}{y}\right)\), we must consider how the values of \(x\) (numerator) and \(y\) (denominator) influence the overall size of the fraction. For a fraction to be as small as possible, we need to achieve two conditions simultaneously:
Let's analyze the given ranges for \(x\) and \(y\):
To make the fraction \(\left(\frac{x}{y}\right)\) as small as possible, we should choose the smallest possible value for \(x\). Based on the range \(3 \le x \le 10\), the absolute minimum value \(x\) can take is 3.
Conversely, to minimize the fraction \(\left(\frac{x}{y}\right)\), we should choose the largest possible value for \(y\). From the range \(5 \le y \le 15\), the absolute maximum value \(y\) can take is 15.
Now, we substitute these chosen extreme values of \(x\) and \(y\) into the expression \(\left(\frac{x}{y}\right)\):
\(\text{Minimum value of } \left(\frac{x}{y}\right) = \frac{\text{Smallest value of } x}{\text{Largest value of } y}\)
\(\text{Minimum value of } \left(\frac{x}{y}\right) = \frac{3}{15}\)
The fraction \(\frac{3}{15}\) can be simplified. Both the numerator (3) and the denominator (15) are divisible by 3. Dividing both by 3, we get:
\(\frac{3 \div 3}{15 \div 3} = \frac{1}{5}\)
Therefore, the minimum value of \(\left(\frac{x}{y}\right)\) is \(\frac{1}{5}\).
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