If 3 ≤ x ≤ 10 and 5 ≤ y ≤ 15 , then maximum value of \(\left(\frac{x}{y}\right)\) is-
To determine the maximum value of the expression \(\left(\frac{x}{y}\right)\) given the ranges for \(x\) and \(y\), we need to consider the properties of fractions. For a fraction to achieve its largest possible value, its numerator (the top part) should be as large as possible, and its denominator (the bottom part) should be as small as possible.
The problem provides specific ranges for the variables \(x\) and \(y\):
To maximize the fraction \(\left(\frac{x}{y}\right)\):
Now, we substitute these identified optimal values into the expression \(\left(\frac{x}{y}\right)\):
Maximum value of \(\left(\frac{x}{y}\right)\) = \(\frac{\text{Maximum value of } x}{\text{Minimum value of } y}\)
Substituting the specific values:
Maximum value = \(\frac{10}{5}\)
Maximum value = \(2\)
Therefore, the maximum value of the expression \(\left(\frac{x}{y}\right)\), based on the given ranges for \(x\) and \(y\), is 2.
| Variable | Given Range | Value Chosen for Maximum \(\left(\frac{x}{y}\right)\) |
|---|---|---|
| \(x\) | \(3 \le x \le 10\) | \(10\) (Maximum of its range) |
| \(y\) | \(5 \le y \le 15\) | \(5\) (Minimum of its range) |
This method ensures we obtain the largest possible ratio by maximizing the numerator and minimizing the denominator within their respective constraints.
Four small squares of side x are cut out of a square of side 12 cm to make a tray by folding the edges. What is the value of x so that the tray has the maximum volume?
If N is a four digit number formed by digits x 1, x 2, x 3and x 4, then maximum value of \(\frac{N}{x_{1}+x_{2}+x_{3}+x_{4}}\) is-